Cyrus' Adventure (Part 1)
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Cyrus is on an adventure to the deep unknown forest, in order to get the mysterious treasure box. After walking for a few days, he found out that a strange door was blocking his way, and there weren't any paths that Cyrus could take. Without choice, he could only try to open the door. There were some numbers on the door and strangely, there was a touch-sensing screen near the side of the door. It showed the alphabet, from A-Z. There were also 4 lines on top of the alphabet buttons. Cyrus pressed a random letter, and it appeared on the first line. He quickly found out that it was a password lock. He cleared the letters and started to look at the four numbers. They are 2, 5, 13 and 34. The question comes. What are the 4 letters? What is the password? Can you help Cyrus solve the problem?
p.s. you can go ask your math teacher for hints
number-sequence
New contributor
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add a comment |
$begingroup$
Cyrus is on an adventure to the deep unknown forest, in order to get the mysterious treasure box. After walking for a few days, he found out that a strange door was blocking his way, and there weren't any paths that Cyrus could take. Without choice, he could only try to open the door. There were some numbers on the door and strangely, there was a touch-sensing screen near the side of the door. It showed the alphabet, from A-Z. There were also 4 lines on top of the alphabet buttons. Cyrus pressed a random letter, and it appeared on the first line. He quickly found out that it was a password lock. He cleared the letters and started to look at the four numbers. They are 2, 5, 13 and 34. The question comes. What are the 4 letters? What is the password? Can you help Cyrus solve the problem?
p.s. you can go ask your math teacher for hints
number-sequence
New contributor
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1
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There are 5 lines but we know we only need 4 letters? Is that a mistake? Should it say "What are the four numbers?" perhaps?
$endgroup$
– Jonathan Allan
10 hours ago
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@JonathanAllan sorry corrected typo
$endgroup$
– K Sharing
3 mins ago
add a comment |
$begingroup$
Cyrus is on an adventure to the deep unknown forest, in order to get the mysterious treasure box. After walking for a few days, he found out that a strange door was blocking his way, and there weren't any paths that Cyrus could take. Without choice, he could only try to open the door. There were some numbers on the door and strangely, there was a touch-sensing screen near the side of the door. It showed the alphabet, from A-Z. There were also 4 lines on top of the alphabet buttons. Cyrus pressed a random letter, and it appeared on the first line. He quickly found out that it was a password lock. He cleared the letters and started to look at the four numbers. They are 2, 5, 13 and 34. The question comes. What are the 4 letters? What is the password? Can you help Cyrus solve the problem?
p.s. you can go ask your math teacher for hints
number-sequence
New contributor
$endgroup$
Cyrus is on an adventure to the deep unknown forest, in order to get the mysterious treasure box. After walking for a few days, he found out that a strange door was blocking his way, and there weren't any paths that Cyrus could take. Without choice, he could only try to open the door. There were some numbers on the door and strangely, there was a touch-sensing screen near the side of the door. It showed the alphabet, from A-Z. There were also 4 lines on top of the alphabet buttons. Cyrus pressed a random letter, and it appeared on the first line. He quickly found out that it was a password lock. He cleared the letters and started to look at the four numbers. They are 2, 5, 13 and 34. The question comes. What are the 4 letters? What is the password? Can you help Cyrus solve the problem?
p.s. you can go ask your math teacher for hints
number-sequence
number-sequence
New contributor
New contributor
edited 4 mins ago
K Sharing
New contributor
asked 11 hours ago
K SharingK Sharing
318
318
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1
$begingroup$
There are 5 lines but we know we only need 4 letters? Is that a mistake? Should it say "What are the four numbers?" perhaps?
$endgroup$
– Jonathan Allan
10 hours ago
$begingroup$
@JonathanAllan sorry corrected typo
$endgroup$
– K Sharing
3 mins ago
add a comment |
1
$begingroup$
There are 5 lines but we know we only need 4 letters? Is that a mistake? Should it say "What are the four numbers?" perhaps?
$endgroup$
– Jonathan Allan
10 hours ago
$begingroup$
@JonathanAllan sorry corrected typo
$endgroup$
– K Sharing
3 mins ago
1
1
$begingroup$
There are 5 lines but we know we only need 4 letters? Is that a mistake? Should it say "What are the four numbers?" perhaps?
$endgroup$
– Jonathan Allan
10 hours ago
$begingroup$
There are 5 lines but we know we only need 4 letters? Is that a mistake? Should it say "What are the four numbers?" perhaps?
$endgroup$
– Jonathan Allan
10 hours ago
$begingroup$
@JonathanAllan sorry corrected typo
$endgroup$
– K Sharing
3 mins ago
$begingroup$
@JonathanAllan sorry corrected typo
$endgroup$
– K Sharing
3 mins ago
add a comment |
2 Answers
2
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oldest
votes
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It's apparent that the numbers
are alternate Fibonacci numbers: 0 1 1 2 3 5 8 13 21 34 etc.
I would try
considering the following correspondence: 1/F 1/I 2/B 3/O 5/N 8/A 13/C 21/C 34/I and entering BNCI if we need four letters, and maybe the complement FIOAC if we need five (one per line).
I have to confess that the problem seems somewhat underdetermined: on the face of it (though I may be missing something) there are several different ways to get from the information we have to a sequence of letters.
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+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
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You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
add a comment |
$begingroup$
If I were Cyrus I'd give these four a go:
A C H U
...because $2$, $5$, $13$, and $34$ are all Fibonacci numbers
($f(n)=f(n-2)+f(n-1)$ with $f(0)=1$ and $f(1)=1$)
i.e.: $1, 1, 2, 3, 5, 8, 13, 21, 34, 55, cdots$
and treating A,B,C,... as $1,2,3,...$ these are what appear to be the missing numbers as letters.
if we need 5 letters (as there are 5 lines) try
A A C H U
"Gesundheit!"
$endgroup$
add a comment |
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$begingroup$
It's apparent that the numbers
are alternate Fibonacci numbers: 0 1 1 2 3 5 8 13 21 34 etc.
I would try
considering the following correspondence: 1/F 1/I 2/B 3/O 5/N 8/A 13/C 21/C 34/I and entering BNCI if we need four letters, and maybe the complement FIOAC if we need five (one per line).
I have to confess that the problem seems somewhat underdetermined: on the face of it (though I may be missing something) there are several different ways to get from the information we have to a sequence of letters.
$endgroup$
$begingroup$
+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
$begingroup$
You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
add a comment |
$begingroup$
It's apparent that the numbers
are alternate Fibonacci numbers: 0 1 1 2 3 5 8 13 21 34 etc.
I would try
considering the following correspondence: 1/F 1/I 2/B 3/O 5/N 8/A 13/C 21/C 34/I and entering BNCI if we need four letters, and maybe the complement FIOAC if we need five (one per line).
I have to confess that the problem seems somewhat underdetermined: on the face of it (though I may be missing something) there are several different ways to get from the information we have to a sequence of letters.
$endgroup$
$begingroup$
+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
$begingroup$
You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
add a comment |
$begingroup$
It's apparent that the numbers
are alternate Fibonacci numbers: 0 1 1 2 3 5 8 13 21 34 etc.
I would try
considering the following correspondence: 1/F 1/I 2/B 3/O 5/N 8/A 13/C 21/C 34/I and entering BNCI if we need four letters, and maybe the complement FIOAC if we need five (one per line).
I have to confess that the problem seems somewhat underdetermined: on the face of it (though I may be missing something) there are several different ways to get from the information we have to a sequence of letters.
$endgroup$
It's apparent that the numbers
are alternate Fibonacci numbers: 0 1 1 2 3 5 8 13 21 34 etc.
I would try
considering the following correspondence: 1/F 1/I 2/B 3/O 5/N 8/A 13/C 21/C 34/I and entering BNCI if we need four letters, and maybe the complement FIOAC if we need five (one per line).
I have to confess that the problem seems somewhat underdetermined: on the face of it (though I may be missing something) there are several different ways to get from the information we have to a sequence of letters.
answered 7 hours ago
Gareth McCaughan♦Gareth McCaughan
61.2k3152236
61.2k3152236
$begingroup$
+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
$begingroup$
You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
add a comment |
$begingroup$
+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
$begingroup$
You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
$begingroup$
+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
$begingroup$
+1 for the comment about having multiple ways to get the letters.
$endgroup$
– ZanyG
3 hours ago
$begingroup$
You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
$begingroup$
You are correct for BNCI!
$endgroup$
– K Sharing
4 mins ago
add a comment |
$begingroup$
If I were Cyrus I'd give these four a go:
A C H U
...because $2$, $5$, $13$, and $34$ are all Fibonacci numbers
($f(n)=f(n-2)+f(n-1)$ with $f(0)=1$ and $f(1)=1$)
i.e.: $1, 1, 2, 3, 5, 8, 13, 21, 34, 55, cdots$
and treating A,B,C,... as $1,2,3,...$ these are what appear to be the missing numbers as letters.
if we need 5 letters (as there are 5 lines) try
A A C H U
"Gesundheit!"
$endgroup$
add a comment |
$begingroup$
If I were Cyrus I'd give these four a go:
A C H U
...because $2$, $5$, $13$, and $34$ are all Fibonacci numbers
($f(n)=f(n-2)+f(n-1)$ with $f(0)=1$ and $f(1)=1$)
i.e.: $1, 1, 2, 3, 5, 8, 13, 21, 34, 55, cdots$
and treating A,B,C,... as $1,2,3,...$ these are what appear to be the missing numbers as letters.
if we need 5 letters (as there are 5 lines) try
A A C H U
"Gesundheit!"
$endgroup$
add a comment |
$begingroup$
If I were Cyrus I'd give these four a go:
A C H U
...because $2$, $5$, $13$, and $34$ are all Fibonacci numbers
($f(n)=f(n-2)+f(n-1)$ with $f(0)=1$ and $f(1)=1$)
i.e.: $1, 1, 2, 3, 5, 8, 13, 21, 34, 55, cdots$
and treating A,B,C,... as $1,2,3,...$ these are what appear to be the missing numbers as letters.
if we need 5 letters (as there are 5 lines) try
A A C H U
"Gesundheit!"
$endgroup$
If I were Cyrus I'd give these four a go:
A C H U
...because $2$, $5$, $13$, and $34$ are all Fibonacci numbers
($f(n)=f(n-2)+f(n-1)$ with $f(0)=1$ and $f(1)=1$)
i.e.: $1, 1, 2, 3, 5, 8, 13, 21, 34, 55, cdots$
and treating A,B,C,... as $1,2,3,...$ these are what appear to be the missing numbers as letters.
if we need 5 letters (as there are 5 lines) try
A A C H U
"Gesundheit!"
answered 10 hours ago
Jonathan AllanJonathan Allan
17.7k14697
17.7k14697
add a comment |
add a comment |
K Sharing is a new contributor. Be nice, and check out our Code of Conduct.
K Sharing is a new contributor. Be nice, and check out our Code of Conduct.
K Sharing is a new contributor. Be nice, and check out our Code of Conduct.
K Sharing is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
There are 5 lines but we know we only need 4 letters? Is that a mistake? Should it say "What are the four numbers?" perhaps?
$endgroup$
– Jonathan Allan
10 hours ago
$begingroup$
@JonathanAllan sorry corrected typo
$endgroup$
– K Sharing
3 mins ago