Can 4 = 6 and 10 = 1000? : Another Grandpa Question
$begingroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
edited 22 hours ago
JonMark Perry
18.5k63888
asked 2 days ago
DEEMDEEM
5,707118104
$endgroup$
|
show 2 more comments
$begingroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
edited 22 hours ago
JonMark Perry
18.5k63888
asked 2 days ago
DEEMDEEM
5,707118104
$endgroup$
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
yesterday
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
yesterday
$begingroup$
And you already have it!
$endgroup$
– DEEM
yesterday
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.
$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
yesterday
|
show 2 more comments
$begingroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
edited 22 hours ago
JonMark Perry
18.5k63888
asked 2 days ago
DEEMDEEM
5,707118104
$endgroup$
Grandpa likes PSE. He is amazed at the smart puzzle solvers who seem to solve any of his riddles. So he constantly tries to think of new challenging questions.
So he says:
"Ask Tom, SteveV, Jafe, Rand, elguest, hex, Bass and other smart guys
Is it possible to prove
4 = 6
and
10 = 1000
using same logic (that is what I call it)
and no math operations?"
uvag guvax ebgguvegrra
knowledge lateral-thinking
knowledge lateral-thinking
edited 22 hours ago
JonMark Perry
18.5k63888
asked 2 days ago
DEEMDEEM
5,707118104
edited 22 hours ago
JonMark Perry
18.5k63888
asked 2 days ago
DEEMDEEM
5,707118104
edited 22 hours ago
JonMark Perry
18.5k63888
edited 22 hours ago
JonMark Perry
18.5k63888
edited 22 hours ago
JonMark Perry
18.5k63888
18.5k63888
asked 2 days ago
DEEMDEEM
5,707118104
asked 2 days ago
DEEMDEEM
5,707118104
asked 2 days ago
DEEMDEEM
5,707118104
5,707118104
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
yesterday
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
yesterday
$begingroup$
And you already have it!
$endgroup$
– DEEM
yesterday
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.
$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
yesterday
|
show 2 more comments
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
yesterday
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
yesterday
$begingroup$
And you already have it!
$endgroup$
– DEEM
yesterday
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.
$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
yesterday
$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
yesterday
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
yesterday
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
yesterday
$begingroup$
And you already have it!
$endgroup$
– DEEM
yesterday
$begingroup$
And you already have it!
$endgroup$
– DEEM
yesterday
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that
2*2 = 4, but we could have accepted that 2*2 = a fluffy white rabbit.$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that
2*2 = 4, but we could have accepted that 2*2 = a fluffy white rabbit.$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
yesterday
|
show 2 more comments
5 Answers
5
active
oldest
votes
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered 2 days ago
Krad CigolKrad Cigol
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
|
show 5 more comments
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
$endgroup$
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
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@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
|
show 1 more comment
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered yesterday
JeffreyJeffrey
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered yesterday
jakeopsjakeops
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered 2 days ago
Krad CigolKrad Cigol
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
|
show 5 more comments
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered 2 days ago
Krad CigolKrad Cigol
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
|
show 5 more comments
$begingroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered 2 days ago
Krad CigolKrad Cigol
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
My final answer:
For 4=6:
In Roman, 4 is IV.
But rot13(IV) is VI!
VI in Roman is 6,
so 4=6.
Similarly
For 1000=10
In Roman, 10 is X.
But rot13(X) is K.
K isn’t roman for 1000, but it does mean 1000.
So 10=1000.
Attempt 2(wrong again!):
My guess would be:
From @Rand al’Thor
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
But I seem to have the answer.
For 10=1000
The number of votes you need for a gold badge is 1000, which is 10 times those for bronze.
For 4=6
I just browsed the six user profiles, and except for Rand al’Thor
and El-Guest, the remaining four have silver or below in the riddle tag.
ORIGINAL ANSWER(INCORRECT):
Partial answer:
4=6
This can be proven by using Roman numerals
4=IV
6=VI
IV=VI
So 4=6
Then for part 2:
10 = 1000 if we consider 0 to have no value - literally!
answered 2 days ago
Krad CigolKrad Cigol
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 23 hours ago
answered 2 days ago
Krad CigolKrad Cigol
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
Krad CigolKrad Cigol
20115
answered 2 days ago
Krad CigolKrad Cigol
20115
20115
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Krad Cigol is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
|
show 5 more comments
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
1
1
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
IV = VI ? I do not get it. There is a different way Krad Cigol
$endgroup$
– DEEM
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
Oh, ok. Is 10=1000 right?
$endgroup$
– Krad Cigol
2 days ago
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
$begingroup$
No. Remember SAME LOGIC for both.
$endgroup$
– DEEM
yesterday
2
2
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
$begingroup$
Hello. You finally have it (Rot13) But 4 = IV and Rot13 IV is VI =6. Please edit your answer @Krad Cigol
$endgroup$
– DEEM
23 hours ago
2
2
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
$begingroup$
Great solve and question @DEEM. $pi = 105$ :)
$endgroup$
– Tom
22 hours ago
|
show 5 more comments
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
$endgroup$
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
|
show 1 more comment
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
$endgroup$
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
|
show 1 more comment
$begingroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
$endgroup$
I think it might be something to do with
the fact that all of the puzzlers mentioned in the question - Tom, SteveV, Jafe, Rand, elguest, hex, Bass - have tag badges (bronze, silver, or gold) in the riddle tag.
Which makes it ironic that
I just edited the riddle tag out of your question because it's not a riddle! :-P
Which then makes me think that the numbers might have something to do with
the requirements for earning a tag badge. Specifically, the number of answers/votes you need for a silver one is 4 times the number you need for a bronze one, while the number you need for a gold one is 10 times that, which comes to 1000 votes. I just don't see the relevance of 6 ...
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
answered yesterday
Rand al'ThorRand al'Thor
69.5k14230464
69.5k14230464
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
|
show 1 more comment
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
$begingroup$
it feels like you are on the right path. if it helps rot13(gur evqqyr gnt vf gur bayl gnt gung unf njneqrq n tbyq (bar-gubhfnaq cbvag) onqtr.)
$endgroup$
– SteveV
yesterday
2
2
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
$begingroup$
How are you so good at this stuff? Do you work? Are you just AI? Ahh so many questions!
$endgroup$
– T James
yesterday
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
@SteveV I (of all people) know that :-P The 6 is still a mystery though ...
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
How do you know it's not some other Tom, other SteveV and so on? Anyone can change his name any time.
$endgroup$
– Thomas Weller
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
@ThomasWeller That's a downside of this puzzle ... but in context, as a PSE regular, I'm pretty sure these are the users meant.
$endgroup$
– Rand al'Thor
yesterday
|
show 1 more comment
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered yesterday
JeffreyJeffrey
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered yesterday
JeffreyJeffrey
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered yesterday
JeffreyJeffrey
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Just going to give this a try. Was not even aware that this stackExchange existed!
4=6 -> 4=IV, 6 = VI
10=1000 -> 10=X, 1000=M
IV=VI
X=M
Step 1, remove all vertical lines
Step 2, cut off the lower half of the character
IV=VI --> V=V --> /=/
X=M --> X=v* --> V=V
*the v is floating in the air, its the "v" part of M once the vertical lines are removed
answered yesterday
JeffreyJeffrey
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
answered yesterday
JeffreyJeffrey
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
JeffreyJeffrey
1914
answered yesterday
JeffreyJeffrey
1914
1914
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Jeffrey is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
add a comment |
$begingroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
$endgroup$
Well...
in many tribal languages, for example that of the Caquintes, numerals higher than two or three are just a word that means "many" (in Caquinte language's case, "oshequi").
So our expressions become "oshequi" = "oshequi" and "oshequi" = "oshequi". Voilà!
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
edited yesterday
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
answered yesterday
LinuxBlanketLinuxBlanket
1,374515
1,374515
add a comment |
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered yesterday
jakeopsjakeops
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered yesterday
jakeopsjakeops
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered yesterday
jakeopsjakeops
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
If you are asking a smart group of guys a question. aka: Tom, SteveV, Jafe, Rand, elguest, hex, Bass and others. They are all part of the same group no matter if its four people or six people
answered yesterday
jakeopsjakeops
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
jakeopsjakeops
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
jakeopsjakeops
1
answered yesterday
jakeopsjakeops
1
1
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
jakeops is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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$begingroup$
i assume rot13(gung gur nafjre vfa'g fvzcyl "ab")?
$endgroup$
– SteveV
yesterday
$begingroup$
Correct SteveV. There is a funny logic to get to the answer
$endgroup$
– DEEM
yesterday
$begingroup$
And you already have it!
$endgroup$
– DEEM
yesterday
$begingroup$
Interesting thing. My university math teacher once said that our math is what we desided to accept long ago. We accepted that
2*2 = 4, but we could have accepted that2*2 = a fluffy white rabbit.$endgroup$
– Eugene Anisiutkin
yesterday
$begingroup$
Also i suppose rot13(lbh unir gb znxr n "abg rdhnyf" fvat vafgrnq "rdhnyf" fvta. Gung fgvpgyl fcrnxvat jba'g or n zngu bcrengvba, ohg n qenjvat bar.) is not the correct answer =)
$endgroup$
– Eugene Anisiutkin
yesterday