Six real numbers so that product of any five is the sixth one
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I believe this is not so hard problem but I got no clue to proceed. The work I did till now. Say the numbers be $a,b,c,d,e, abcde$ . Then, $b.c.d.e.abcde=a$ hence $bcde= +-1$ . Basically I couldn't even find a single occasion where such things occcur except all of these numbers being either $1$ or $-1$ . Are these all cases?
combinatorics
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edited 39 mins ago
Vinyl_coat_jawa
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asked 41 mins ago
ChakSayantan