How to apply float precision (type specifier) in a conditional f-string?












6















I have the following f-string I want to print out on the condition the variable is available:



f"Percent growth: {self.percent_growth if True else 'No data yet'}"


Which results in:



Percent growth : 0.19824077757643577


So normally I'd use a type specifier for float precision like this:



f'{self.percent_growth:.2f}'


Which would result in:



0.198


But that messes with the if-statement in this case. Either it fails because:



f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"


The if statement becomes unreachable.
Or in the second way: 



f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"


The f-string fails whenever the condition leads to the else clause.



So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?






python python-3.x f-string







share|improve this question


















  • 1





    I formulated the question this way so it was clear no matter what condition it fails to even execute.

    – NoSplitSherlock
    2 hours ago
















6















I have the following f-string I want to print out on the condition the variable is available:



f"Percent growth: {self.percent_growth if True else 'No data yet'}"


Which results in:



Percent growth : 0.19824077757643577


So normally I'd use a type specifier for float precision like this:



f'{self.percent_growth:.2f}'


Which would result in:



0.198


But that messes with the if-statement in this case. Either it fails because:



f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"


The if statement becomes unreachable.
Or in the second way: 



f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"


The f-string fails whenever the condition leads to the else clause.



So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?






python python-3.x f-string







share|improve this question


















  • 1





    I formulated the question this way so it was clear no matter what condition it fails to even execute.

    – NoSplitSherlock
    2 hours ago














6












6








6








I have the following f-string I want to print out on the condition the variable is available:



f"Percent growth: {self.percent_growth if True else 'No data yet'}"


Which results in:



Percent growth : 0.19824077757643577


So normally I'd use a type specifier for float precision like this:



f'{self.percent_growth:.2f}'


Which would result in:



0.198


But that messes with the if-statement in this case. Either it fails because:



f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"


The if statement becomes unreachable.
Or in the second way: 



f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"


The f-string fails whenever the condition leads to the else clause.



So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?






python python-3.x f-string







share|improve this question














I have the following f-string I want to print out on the condition the variable is available:



f"Percent growth: {self.percent_growth if True else 'No data yet'}"


Which results in:



Percent growth : 0.19824077757643577


So normally I'd use a type specifier for float precision like this:



f'{self.percent_growth:.2f}'


Which would result in:



0.198


But that messes with the if-statement in this case. Either it fails because:



f"Percent profit : {self.percent_profit:.2f if True else 'None yet'}"


The if statement becomes unreachable.
Or in the second way: 



f"Percent profit : {self.percent_profit if True else 'None yet':.2f}"


The f-string fails whenever the condition leads to the else clause.



So my question is, how can I apply the float precision within the f-string when the f-string can result in two types?






python python-3.x f-string




python python-3.x f-string






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 4 hours ago









NoSplitSherlockNoSplitSherlock

1027




1027








  • 1





    I formulated the question this way so it was clear no matter what condition it fails to even execute.

    – NoSplitSherlock
    2 hours ago














  • 1





    I formulated the question this way so it was clear no matter what condition it fails to even execute.

    – NoSplitSherlock
    2 hours ago








1




1





I formulated the question this way so it was clear no matter what condition it fails to even execute.

– NoSplitSherlock
2 hours ago





I formulated the question this way so it was clear no matter what condition it fails to even execute.

– NoSplitSherlock
2 hours ago












3 Answers
3






active

oldest

votes


















7














You could use another f-string for your first condition:



f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"


Admittedly not ideal, but it does the job.






share|improve this answer



















  • 1





    Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

    – Idlehands
    4 hours ago













  • @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

    – NoSplitSherlock
    4 hours ago






  • 1





    @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

    – Nikolas Stevenson-Molnar
    4 hours ago






  • 1





    @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

    – Nikolas Stevenson-Molnar
    3 hours ago











  • @PatrickArtner Absolutely, that works too.

    – Nikolas Stevenson-Molnar
    3 hours ago



















2














You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:



for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)

    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")

    # you need to put '.05f' into a string for this to work and not complain


Output:



Percent growth: 2.56235

Percent growth: 0.90000

Percent growth: No data yet





share|improve this answer





















  • 1





    I love how hacky this is.

    – NoSplitSherlock
    3 hours ago



















1














I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:



value = f'{self.percent_profit:.2f}' if True else 'No data yet'

print(f"Percent profit : {value}")





share|improve this answer























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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    You could use another f-string for your first condition:



    f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"


    Admittedly not ideal, but it does the job.






    share|improve this answer



















    • 1





      Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

      – Idlehands
      4 hours ago













    • @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

      – NoSplitSherlock
      4 hours ago






    • 1





      @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

      – Nikolas Stevenson-Molnar
      4 hours ago






    • 1





      @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

      – Nikolas Stevenson-Molnar
      3 hours ago











    • @PatrickArtner Absolutely, that works too.

      – Nikolas Stevenson-Molnar
      3 hours ago
















    7














    You could use another f-string for your first condition:



    f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"


    Admittedly not ideal, but it does the job.






    share|improve this answer



















    • 1





      Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

      – Idlehands
      4 hours ago













    • @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

      – NoSplitSherlock
      4 hours ago






    • 1





      @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

      – Nikolas Stevenson-Molnar
      4 hours ago






    • 1





      @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

      – Nikolas Stevenson-Molnar
      3 hours ago











    • @PatrickArtner Absolutely, that works too.

      – Nikolas Stevenson-Molnar
      3 hours ago














    7












    7








    7







    You could use another f-string for your first condition:



    f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"


    Admittedly not ideal, but it does the job.






    share|improve this answer













    You could use another f-string for your first condition:



    f"Percent profit : {f'{self.percent_profit:.2f}' if True else 'None yet'}"


    Admittedly not ideal, but it does the job.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 4 hours ago









    Nikolas Stevenson-MolnarNikolas Stevenson-Molnar

    1,216714




    1,216714








    • 1





      Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

      – Idlehands
      4 hours ago













    • @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

      – NoSplitSherlock
      4 hours ago






    • 1





      @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

      – Nikolas Stevenson-Molnar
      4 hours ago






    • 1





      @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

      – Nikolas Stevenson-Molnar
      3 hours ago











    • @PatrickArtner Absolutely, that works too.

      – Nikolas Stevenson-Molnar
      3 hours ago














    • 1





      Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

      – Idlehands
      4 hours ago













    • @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

      – NoSplitSherlock
      4 hours ago






    • 1





      @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

      – Nikolas Stevenson-Molnar
      4 hours ago






    • 1





      @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

      – Nikolas Stevenson-Molnar
      3 hours ago











    • @PatrickArtner Absolutely, that works too.

      – Nikolas Stevenson-Molnar
      3 hours ago








    1




    1





    Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

    – Idlehands
    4 hours ago







    Another way is using str.format but I don't think it's any different. f"Percent profit : {'{:.2f}'.format(self.percent_format) if True else 'None yet'}" This is as simple as it gets if OP insists putting the condition within the f string itself.

    – Idlehands
    4 hours ago















    @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

    – NoSplitSherlock
    4 hours ago





    @Idlehands Isn't it strange though that I can format strings and use conditionals, but not both at the same time?

    – NoSplitSherlock
    4 hours ago




    1




    1





    @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

    – Nikolas Stevenson-Molnar
    4 hours ago





    @NoSplitSherlock If both outcomes of the the conditional were the same, you could. I think the tricky part of your example is that your conditional will yield either a float or a string.

    – Nikolas Stevenson-Molnar
    4 hours ago




    1




    1





    @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

    – Nikolas Stevenson-Molnar
    3 hours ago





    @PatrickArtner see the OP’s question and code sample. The if True is a stand in for any conditional.

    – Nikolas Stevenson-Molnar
    3 hours ago













    @PatrickArtner Absolutely, that works too.

    – Nikolas Stevenson-Molnar
    3 hours ago





    @PatrickArtner Absolutely, that works too.

    – Nikolas Stevenson-Molnar
    3 hours ago













    2














    You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:



    for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)
    
    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")
    
    # you need to put '.05f' into a string for this to work and not complain


    Output:



    Percent growth: 2.56235
    
Percent growth: 0.90000
    
Percent growth: No data yet





    share|improve this answer





















    • 1





      I love how hacky this is.

      – NoSplitSherlock
      3 hours ago
















    2














    You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:



    for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)
    
    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")
    
    # you need to put '.05f' into a string for this to work and not complain


    Output:



    Percent growth: 2.56235
    
Percent growth: 0.90000
    
Percent growth: No data yet





    share|improve this answer





















    • 1





      I love how hacky this is.

      – NoSplitSherlock
      3 hours ago














    2












    2








    2







    You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:



    for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)
    
    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")
    
    # you need to put '.05f' into a string for this to work and not complain


    Output:



    Percent growth: 2.56235
    
Percent growth: 0.90000
    
Percent growth: No data yet





    share|improve this answer















    You can use a ternary for the formatter as well - no need to stack 2 f-strings like Nikolas answer does:



    for pg in (2.562345678, 0.9, None):   # 0.0 is also Falsy - careful ;o)
    
    print(f"Percent Growth: {pg if pg else 'No data yet':{'.05f' if pg else ''}}")
    
    # you need to put '.05f' into a string for this to work and not complain


    Output:



    Percent growth: 2.56235
    
Percent growth: 0.90000
    
Percent growth: No data yet






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 3 hours ago

























    answered 3 hours ago









    Patrick ArtnerPatrick Artner

    24.9k62443




    24.9k62443








    • 1





      I love how hacky this is.

      – NoSplitSherlock
      3 hours ago














    • 1





      I love how hacky this is.

      – NoSplitSherlock
      3 hours ago








    1




    1





    I love how hacky this is.

    – NoSplitSherlock
    3 hours ago





    I love how hacky this is.

    – NoSplitSherlock
    3 hours ago











    1














    I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:



    value = f'{self.percent_profit:.2f}' if True else 'No data yet'
    
print(f"Percent profit : {value}")





    share|improve this answer




























      1














      I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:



      value = f'{self.percent_profit:.2f}' if True else 'No data yet'
      
print(f"Percent profit : {value}")





      share|improve this answer


























        1












        1








        1







        I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:



        value = f'{self.percent_profit:.2f}' if True else 'No data yet'
        
print(f"Percent profit : {value}")





        share|improve this answer













        I think the f string within f string answer is as simple as it gets, but if you want a little bit more readability, consider moving the condition outside the f string:



        value = f'{self.percent_profit:.2f}' if True else 'No data yet'
        
print(f"Percent profit : {value}")






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 4 hours ago









        IdlehandsIdlehands

        5,6551620




        5,6551620






























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