Is Q a vector space over Z or Q?












4












$begingroup$


Is $Q^n$ a vector space over $Z$ or over $Q$?



$Q^n$ is clearly not a vector space over $R$, because scalar multiplication of some $q in Q$ by $pi$ renders $pi q$, which is irrational.










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  • 4




    $begingroup$
    It doesn't make sense to be a vector space over $mathbb Z$, because $mathbb Z$ is not a field. However, it is a vector space over $mathbb Q$.
    $endgroup$
    – Ashwin Trisal
    41 mins ago










  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – José Carlos Santos
    39 mins ago
















4












$begingroup$


Is $Q^n$ a vector space over $Z$ or over $Q$?



$Q^n$ is clearly not a vector space over $R$, because scalar multiplication of some $q in Q$ by $pi$ renders $pi q$, which is irrational.










share|cite|improve this question







New contributor




Cactus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 4




    $begingroup$
    It doesn't make sense to be a vector space over $mathbb Z$, because $mathbb Z$ is not a field. However, it is a vector space over $mathbb Q$.
    $endgroup$
    – Ashwin Trisal
    41 mins ago










  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – José Carlos Santos
    39 mins ago














4












4








4





$begingroup$


Is $Q^n$ a vector space over $Z$ or over $Q$?



$Q^n$ is clearly not a vector space over $R$, because scalar multiplication of some $q in Q$ by $pi$ renders $pi q$, which is irrational.










share|cite|improve this question







New contributor




Cactus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Is $Q^n$ a vector space over $Z$ or over $Q$?



$Q^n$ is clearly not a vector space over $R$, because scalar multiplication of some $q in Q$ by $pi$ renders $pi q$, which is irrational.







linear-algebra vector-spaces vectors






share|cite|improve this question







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Check out our Code of Conduct.











share|cite|improve this question







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Cactus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






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asked 42 mins ago









CactusCactus

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Cactus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Cactus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 4




    $begingroup$
    It doesn't make sense to be a vector space over $mathbb Z$, because $mathbb Z$ is not a field. However, it is a vector space over $mathbb Q$.
    $endgroup$
    – Ashwin Trisal
    41 mins ago










  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – José Carlos Santos
    39 mins ago














  • 4




    $begingroup$
    It doesn't make sense to be a vector space over $mathbb Z$, because $mathbb Z$ is not a field. However, it is a vector space over $mathbb Q$.
    $endgroup$
    – Ashwin Trisal
    41 mins ago










  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – José Carlos Santos
    39 mins ago








4




4




$begingroup$
It doesn't make sense to be a vector space over $mathbb Z$, because $mathbb Z$ is not a field. However, it is a vector space over $mathbb Q$.
$endgroup$
– Ashwin Trisal
41 mins ago




$begingroup$
It doesn't make sense to be a vector space over $mathbb Z$, because $mathbb Z$ is not a field. However, it is a vector space over $mathbb Q$.
$endgroup$
– Ashwin Trisal
41 mins ago












$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– José Carlos Santos
39 mins ago




$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– José Carlos Santos
39 mins ago










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$begingroup$

You can't have a vector space over $Bbb Z$. By definition, a vector space is required to be over a field. If you take away the field requirement, what you're left with is calles a module. And yes, $Bbb Q^n$ is definitely a $Bbb Z$-module.



That being said, there is a list of $10$ requirements for a space like $Bbb Q^n$ to be a vector space over a field like $Bbb Q$. All of them should be easily verifiable. So yes, $Bbb Q^n$ is a vector space over $Bbb Q$.






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    1 Answer
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    1 Answer
    1






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    active

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    7












    $begingroup$

    You can't have a vector space over $Bbb Z$. By definition, a vector space is required to be over a field. If you take away the field requirement, what you're left with is calles a module. And yes, $Bbb Q^n$ is definitely a $Bbb Z$-module.



    That being said, there is a list of $10$ requirements for a space like $Bbb Q^n$ to be a vector space over a field like $Bbb Q$. All of them should be easily verifiable. So yes, $Bbb Q^n$ is a vector space over $Bbb Q$.






    share|cite|improve this answer









    $endgroup$


















      7












      $begingroup$

      You can't have a vector space over $Bbb Z$. By definition, a vector space is required to be over a field. If you take away the field requirement, what you're left with is calles a module. And yes, $Bbb Q^n$ is definitely a $Bbb Z$-module.



      That being said, there is a list of $10$ requirements for a space like $Bbb Q^n$ to be a vector space over a field like $Bbb Q$. All of them should be easily verifiable. So yes, $Bbb Q^n$ is a vector space over $Bbb Q$.






      share|cite|improve this answer









      $endgroup$
















        7












        7








        7





        $begingroup$

        You can't have a vector space over $Bbb Z$. By definition, a vector space is required to be over a field. If you take away the field requirement, what you're left with is calles a module. And yes, $Bbb Q^n$ is definitely a $Bbb Z$-module.



        That being said, there is a list of $10$ requirements for a space like $Bbb Q^n$ to be a vector space over a field like $Bbb Q$. All of them should be easily verifiable. So yes, $Bbb Q^n$ is a vector space over $Bbb Q$.






        share|cite|improve this answer









        $endgroup$



        You can't have a vector space over $Bbb Z$. By definition, a vector space is required to be over a field. If you take away the field requirement, what you're left with is calles a module. And yes, $Bbb Q^n$ is definitely a $Bbb Z$-module.



        That being said, there is a list of $10$ requirements for a space like $Bbb Q^n$ to be a vector space over a field like $Bbb Q$. All of them should be easily verifiable. So yes, $Bbb Q^n$ is a vector space over $Bbb Q$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 40 mins ago









        ArthurArthur

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        113k7110193






















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