Divisible Dates
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The day of the month, and the month of the year, often divide the year. Most recently it happened on January 3, 2019 because both 1 (January) and 3 divide 2019.
In our era, since 1/1/1, which years have had the most such dates?
arithmetic
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add a comment |
$begingroup$
The day of the month, and the month of the year, often divide the year. Most recently it happened on January 3, 2019 because both 1 (January) and 3 divide 2019.
In our era, since 1/1/1, which years have had the most such dates?
arithmetic
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For clarification: Is a divisible date one in which either the day or month divide the year, or one in with both do?
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– Van
4 hours ago
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@Van Yes, both.
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– Bernardo Recamán Santos
4 hours ago
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can we solve this with some code? :)
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– Flying_whale
4 hours ago
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@Flying_whale: Go!
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– Bernardo Recamán Santos
4 hours ago
add a comment |
$begingroup$
The day of the month, and the month of the year, often divide the year. Most recently it happened on January 3, 2019 because both 1 (January) and 3 divide 2019.
In our era, since 1/1/1, which years have had the most such dates?
arithmetic
$endgroup$
The day of the month, and the month of the year, often divide the year. Most recently it happened on January 3, 2019 because both 1 (January) and 3 divide 2019.
In our era, since 1/1/1, which years have had the most such dates?
arithmetic
arithmetic
asked 4 hours ago
Bernardo Recamán SantosBernardo Recamán Santos
2,3731242
2,3731242
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For clarification: Is a divisible date one in which either the day or month divide the year, or one in with both do?
$endgroup$
– Van
4 hours ago
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@Van Yes, both.
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– Bernardo Recamán Santos
4 hours ago
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can we solve this with some code? :)
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– Flying_whale
4 hours ago
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@Flying_whale: Go!
$endgroup$
– Bernardo Recamán Santos
4 hours ago
add a comment |
$begingroup$
For clarification: Is a divisible date one in which either the day or month divide the year, or one in with both do?
$endgroup$
– Van
4 hours ago
$begingroup$
@Van Yes, both.
$endgroup$
– Bernardo Recamán Santos
4 hours ago
$begingroup$
can we solve this with some code? :)
$endgroup$
– Flying_whale
4 hours ago
$begingroup$
@Flying_whale: Go!
$endgroup$
– Bernardo Recamán Santos
4 hours ago
$begingroup$
For clarification: Is a divisible date one in which either the day or month divide the year, or one in with both do?
$endgroup$
– Van
4 hours ago
$begingroup$
For clarification: Is a divisible date one in which either the day or month divide the year, or one in with both do?
$endgroup$
– Van
4 hours ago
$begingroup$
@Van Yes, both.
$endgroup$
– Bernardo Recamán Santos
4 hours ago
$begingroup$
@Van Yes, both.
$endgroup$
– Bernardo Recamán Santos
4 hours ago
$begingroup$
can we solve this with some code? :)
$endgroup$
– Flying_whale
4 hours ago
$begingroup$
can we solve this with some code? :)
$endgroup$
– Flying_whale
4 hours ago
$begingroup$
@Flying_whale: Go!
$endgroup$
– Bernardo Recamán Santos
4 hours ago
$begingroup$
@Flying_whale: Go!
$endgroup$
– Bernardo Recamán Santos
4 hours ago
add a comment |
4 Answers
4
active
oldest
votes
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I'm going to go with
1680
factors:
1,2,3,4,5,6,7,8,10,12,14,15,16,20,21,24,28,30
So it hits on
179 days (10 months times 18 days, minus 30th of February)
Method:
Looked up
Highly composite numbers, picked the largest that's smaller than 2019.
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add a comment |
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I found
with a bit of code i found 1680 with 179 dates you can run it here : https://rextester.com/YITA38880
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add a comment |
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I'd be surprised if you can beat:
1080. It equals $2^3times3^3times5$, and so covers $1,2,3,4,5,6,8,9,10,12,15,18,20,24,27,30$ for days and $1,2,3,4,5,6,8,9,10,12$ for months.
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add a comment |
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I believe I can beat JonMark Perry's answer:
1260 = 2 x2 x3 x3 x5 x7
For months, I can get 1, 2, 3, 4, 5, 6, 7, 9, 10, & 12 (10 - same).
But for days, I get:
1, 2, 3, 4, 5, 6, 7, 9, 10, 12 & 14, 15, 18, 20, 21, 28, 30 (17 - one more than Jon)
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add a comment |
Your Answer
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I'm going to go with
1680
factors:
1,2,3,4,5,6,7,8,10,12,14,15,16,20,21,24,28,30
So it hits on
179 days (10 months times 18 days, minus 30th of February)
Method:
Looked up
Highly composite numbers, picked the largest that's smaller than 2019.
$endgroup$
add a comment |
$begingroup$
I'm going to go with
1680
factors:
1,2,3,4,5,6,7,8,10,12,14,15,16,20,21,24,28,30
So it hits on
179 days (10 months times 18 days, minus 30th of February)
Method:
Looked up
Highly composite numbers, picked the largest that's smaller than 2019.
$endgroup$
add a comment |
$begingroup$
I'm going to go with
1680
factors:
1,2,3,4,5,6,7,8,10,12,14,15,16,20,21,24,28,30
So it hits on
179 days (10 months times 18 days, minus 30th of February)
Method:
Looked up
Highly composite numbers, picked the largest that's smaller than 2019.
$endgroup$
I'm going to go with
1680
factors:
1,2,3,4,5,6,7,8,10,12,14,15,16,20,21,24,28,30
So it hits on
179 days (10 months times 18 days, minus 30th of February)
Method:
Looked up
Highly composite numbers, picked the largest that's smaller than 2019.
answered 3 hours ago
BassBass
28.5k469175
28.5k469175
add a comment |
add a comment |
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I found
with a bit of code i found 1680 with 179 dates you can run it here : https://rextester.com/YITA38880
$endgroup$
add a comment |
$begingroup$
I found
with a bit of code i found 1680 with 179 dates you can run it here : https://rextester.com/YITA38880
$endgroup$
add a comment |
$begingroup$
I found
with a bit of code i found 1680 with 179 dates you can run it here : https://rextester.com/YITA38880
$endgroup$
I found
with a bit of code i found 1680 with 179 dates you can run it here : https://rextester.com/YITA38880
edited 11 secs ago
answered 3 hours ago
Flying_whaleFlying_whale
1,559123
1,559123
add a comment |
add a comment |
$begingroup$
I'd be surprised if you can beat:
1080. It equals $2^3times3^3times5$, and so covers $1,2,3,4,5,6,8,9,10,12,15,18,20,24,27,30$ for days and $1,2,3,4,5,6,8,9,10,12$ for months.
$endgroup$
add a comment |
$begingroup$
I'd be surprised if you can beat:
1080. It equals $2^3times3^3times5$, and so covers $1,2,3,4,5,6,8,9,10,12,15,18,20,24,27,30$ for days and $1,2,3,4,5,6,8,9,10,12$ for months.
$endgroup$
add a comment |
$begingroup$
I'd be surprised if you can beat:
1080. It equals $2^3times3^3times5$, and so covers $1,2,3,4,5,6,8,9,10,12,15,18,20,24,27,30$ for days and $1,2,3,4,5,6,8,9,10,12$ for months.
$endgroup$
I'd be surprised if you can beat:
1080. It equals $2^3times3^3times5$, and so covers $1,2,3,4,5,6,8,9,10,12,15,18,20,24,27,30$ for days and $1,2,3,4,5,6,8,9,10,12$ for months.
answered 4 hours ago
JonMark PerryJonMark Perry
18.6k63888
18.6k63888
add a comment |
add a comment |
$begingroup$
I believe I can beat JonMark Perry's answer:
1260 = 2 x2 x3 x3 x5 x7
For months, I can get 1, 2, 3, 4, 5, 6, 7, 9, 10, & 12 (10 - same).
But for days, I get:
1, 2, 3, 4, 5, 6, 7, 9, 10, 12 & 14, 15, 18, 20, 21, 28, 30 (17 - one more than Jon)
$endgroup$
add a comment |
$begingroup$
I believe I can beat JonMark Perry's answer:
1260 = 2 x2 x3 x3 x5 x7
For months, I can get 1, 2, 3, 4, 5, 6, 7, 9, 10, & 12 (10 - same).
But for days, I get:
1, 2, 3, 4, 5, 6, 7, 9, 10, 12 & 14, 15, 18, 20, 21, 28, 30 (17 - one more than Jon)
$endgroup$
add a comment |
$begingroup$
I believe I can beat JonMark Perry's answer:
1260 = 2 x2 x3 x3 x5 x7
For months, I can get 1, 2, 3, 4, 5, 6, 7, 9, 10, & 12 (10 - same).
But for days, I get:
1, 2, 3, 4, 5, 6, 7, 9, 10, 12 & 14, 15, 18, 20, 21, 28, 30 (17 - one more than Jon)
$endgroup$
I believe I can beat JonMark Perry's answer:
1260 = 2 x2 x3 x3 x5 x7
For months, I can get 1, 2, 3, 4, 5, 6, 7, 9, 10, & 12 (10 - same).
But for days, I get:
1, 2, 3, 4, 5, 6, 7, 9, 10, 12 & 14, 15, 18, 20, 21, 28, 30 (17 - one more than Jon)
answered 4 hours ago
VanVan
3414
3414
add a comment |
add a comment |
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$begingroup$
For clarification: Is a divisible date one in which either the day or month divide the year, or one in with both do?
$endgroup$
– Van
4 hours ago
$begingroup$
@Van Yes, both.
$endgroup$
– Bernardo Recamán Santos
4 hours ago
$begingroup$
can we solve this with some code? :)
$endgroup$
– Flying_whale
4 hours ago
$begingroup$
@Flying_whale: Go!
$endgroup$
– Bernardo Recamán Santos
4 hours ago