“is” operation returns false even though two objects have same id
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Two python objects have the same id but "is" operation returns false as shown below:
a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))
print(c.data is a.data)
print(id(c.data) == id(a.data))
Here is the actual output:
id(c.data) 241233112
id(a.data) 241233112
False
True
My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!
python numpy
|
show 7 more comments
Two python objects have the same id but "is" operation returns false as shown below:
a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))
print(c.data is a.data)
print(id(c.data) == id(a.data))
Here is the actual output:
id(c.data) 241233112
id(a.data) 241233112
False
True
My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!
python numpy
1
@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.
– chepner
1 hour ago
2
@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.
– chepner
1 hour ago
1
@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.
– juanpa.arrivillaga
1 hour ago
1
References aren't shared between two variables; each variable is a reference to the object it refers to.
– chepner
55 mins ago
1
@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.
– juanpa.arrivillaga
45 mins ago
|
show 7 more comments
Two python objects have the same id but "is" operation returns false as shown below:
a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))
print(c.data is a.data)
print(id(c.data) == id(a.data))
Here is the actual output:
id(c.data) 241233112
id(a.data) 241233112
False
True
My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!
python numpy
Two python objects have the same id but "is" operation returns false as shown below:
a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))
print(c.data is a.data)
print(id(c.data) == id(a.data))
Here is the actual output:
id(c.data) 241233112
id(a.data) 241233112
False
True
My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!
python numpy
python numpy
edited 1 hour ago
ribitskiyb
376
376
asked 1 hour ago
drminixdrminix
463
463
1
@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.
– chepner
1 hour ago
2
@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.
– chepner
1 hour ago
1
@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.
– juanpa.arrivillaga
1 hour ago
1
References aren't shared between two variables; each variable is a reference to the object it refers to.
– chepner
55 mins ago
1
@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.
– juanpa.arrivillaga
45 mins ago
|
show 7 more comments
1
@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.
– chepner
1 hour ago
2
@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.
– chepner
1 hour ago
1
@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.
– juanpa.arrivillaga
1 hour ago
1
References aren't shared between two variables; each variable is a reference to the object it refers to.
– chepner
55 mins ago
1
@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.
– juanpa.arrivillaga
45 mins ago
1
1
@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.
– chepner
1 hour ago
@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.
– chepner
1 hour ago
2
2
@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.
– chepner
1 hour ago
@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.
– chepner
1 hour ago
1
1
@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.
– juanpa.arrivillaga
1 hour ago
@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.
– juanpa.arrivillaga
1 hour ago
1
1
References aren't shared between two variables; each variable is a reference to the object it refers to.
– chepner
55 mins ago
References aren't shared between two variables; each variable is a reference to the object it refers to.
– chepner
55 mins ago
1
1
@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.
– juanpa.arrivillaga
45 mins ago
@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.
– juanpa.arrivillaga
45 mins ago
|
show 7 more comments
2 Answers
2
active
oldest
votes
a.data
and c.data
both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.
In your first if
statement, the objects have to co-exist while is
checks if they are identical, which they are not.
In the second if
statement, each object is released as soon as id
returns its id.
If you save references to both objects, keeping them alive, you can see they are not the same object.
r0 = a.data
r1 = c.data
assert r0 is not r1
2
what is confusing is the fact thatdata
looks like an attribute, but is probably a property
– Jean-François Fabre♦
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
2
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
add a comment |
In [62]: a = np.arange(12).reshape(2,-1)
...: c = a.reshape(12,1)
.data
returns a memoryview
object. id
just gives the id of that object; it's not the value of the object, or any indication of where a
databuffer is located.
In [63]: a.data
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview
https://docs.python.org/3/library/stdtypes.html#memoryview
If you want to verify that a
and c
share a data buffer, I find the __array_interface__
to be a better tool.
In [66]: a.__array_interface__['data']
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)
It even shows the offset produced by slicing - here 24 bytes, 3*8
In [68]: c[3:].__array_interface__['data']
Out[68]: (50988664, False)
I haven't seen much use of a.data
. It can be used as the buffer
object when creating a new array with ndarray
:
In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data)
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)
But normally we create new arrays with shared memory with slicing or np.array
(copy=False).
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
a.data
and c.data
both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.
In your first if
statement, the objects have to co-exist while is
checks if they are identical, which they are not.
In the second if
statement, each object is released as soon as id
returns its id.
If you save references to both objects, keeping them alive, you can see they are not the same object.
r0 = a.data
r1 = c.data
assert r0 is not r1
2
what is confusing is the fact thatdata
looks like an attribute, but is probably a property
– Jean-François Fabre♦
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
2
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
add a comment |
a.data
and c.data
both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.
In your first if
statement, the objects have to co-exist while is
checks if they are identical, which they are not.
In the second if
statement, each object is released as soon as id
returns its id.
If you save references to both objects, keeping them alive, you can see they are not the same object.
r0 = a.data
r1 = c.data
assert r0 is not r1
2
what is confusing is the fact thatdata
looks like an attribute, but is probably a property
– Jean-François Fabre♦
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
2
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
add a comment |
a.data
and c.data
both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.
In your first if
statement, the objects have to co-exist while is
checks if they are identical, which they are not.
In the second if
statement, each object is released as soon as id
returns its id.
If you save references to both objects, keeping them alive, you can see they are not the same object.
r0 = a.data
r1 = c.data
assert r0 is not r1
a.data
and c.data
both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.
In your first if
statement, the objects have to co-exist while is
checks if they are identical, which they are not.
In the second if
statement, each object is released as soon as id
returns its id.
If you save references to both objects, keeping them alive, you can see they are not the same object.
r0 = a.data
r1 = c.data
assert r0 is not r1
edited 1 hour ago
answered 1 hour ago
chepnerchepner
262k35251345
262k35251345
2
what is confusing is the fact thatdata
looks like an attribute, but is probably a property
– Jean-François Fabre♦
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
2
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
add a comment |
2
what is confusing is the fact thatdata
looks like an attribute, but is probably a property
– Jean-François Fabre♦
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
2
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
2
2
what is confusing is the fact that
data
looks like an attribute, but is probably a property– Jean-François Fabre♦
1 hour ago
what is confusing is the fact that
data
looks like an attribute, but is probably a property– Jean-François Fabre♦
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
In my tests, the id's are different in the first run, but change to become the same on subsequent runs.
– amanb
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
@Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute
– C.Nivs
1 hour ago
2
2
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.
– Jean-François Fabre♦
1 hour ago
add a comment |
In [62]: a = np.arange(12).reshape(2,-1)
...: c = a.reshape(12,1)
.data
returns a memoryview
object. id
just gives the id of that object; it's not the value of the object, or any indication of where a
databuffer is located.
In [63]: a.data
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview
https://docs.python.org/3/library/stdtypes.html#memoryview
If you want to verify that a
and c
share a data buffer, I find the __array_interface__
to be a better tool.
In [66]: a.__array_interface__['data']
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)
It even shows the offset produced by slicing - here 24 bytes, 3*8
In [68]: c[3:].__array_interface__['data']
Out[68]: (50988664, False)
I haven't seen much use of a.data
. It can be used as the buffer
object when creating a new array with ndarray
:
In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data)
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)
But normally we create new arrays with shared memory with slicing or np.array
(copy=False).
add a comment |
In [62]: a = np.arange(12).reshape(2,-1)
...: c = a.reshape(12,1)
.data
returns a memoryview
object. id
just gives the id of that object; it's not the value of the object, or any indication of where a
databuffer is located.
In [63]: a.data
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview
https://docs.python.org/3/library/stdtypes.html#memoryview
If you want to verify that a
and c
share a data buffer, I find the __array_interface__
to be a better tool.
In [66]: a.__array_interface__['data']
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)
It even shows the offset produced by slicing - here 24 bytes, 3*8
In [68]: c[3:].__array_interface__['data']
Out[68]: (50988664, False)
I haven't seen much use of a.data
. It can be used as the buffer
object when creating a new array with ndarray
:
In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data)
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)
But normally we create new arrays with shared memory with slicing or np.array
(copy=False).
add a comment |
In [62]: a = np.arange(12).reshape(2,-1)
...: c = a.reshape(12,1)
.data
returns a memoryview
object. id
just gives the id of that object; it's not the value of the object, or any indication of where a
databuffer is located.
In [63]: a.data
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview
https://docs.python.org/3/library/stdtypes.html#memoryview
If you want to verify that a
and c
share a data buffer, I find the __array_interface__
to be a better tool.
In [66]: a.__array_interface__['data']
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)
It even shows the offset produced by slicing - here 24 bytes, 3*8
In [68]: c[3:].__array_interface__['data']
Out[68]: (50988664, False)
I haven't seen much use of a.data
. It can be used as the buffer
object when creating a new array with ndarray
:
In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data)
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)
But normally we create new arrays with shared memory with slicing or np.array
(copy=False).
In [62]: a = np.arange(12).reshape(2,-1)
...: c = a.reshape(12,1)
.data
returns a memoryview
object. id
just gives the id of that object; it's not the value of the object, or any indication of where a
databuffer is located.
In [63]: a.data
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview
https://docs.python.org/3/library/stdtypes.html#memoryview
If you want to verify that a
and c
share a data buffer, I find the __array_interface__
to be a better tool.
In [66]: a.__array_interface__['data']
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)
It even shows the offset produced by slicing - here 24 bytes, 3*8
In [68]: c[3:].__array_interface__['data']
Out[68]: (50988664, False)
I haven't seen much use of a.data
. It can be used as the buffer
object when creating a new array with ndarray
:
In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data)
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)
But normally we create new arrays with shared memory with slicing or np.array
(copy=False).
edited 1 hour ago
answered 1 hour ago
hpauljhpaulj
118k787160
118k787160
add a comment |
add a comment |
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1
@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.
– chepner
1 hour ago
2
@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.
– chepner
1 hour ago
1
@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.
– juanpa.arrivillaga
1 hour ago
1
References aren't shared between two variables; each variable is a reference to the object it refers to.
– chepner
55 mins ago
1
@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.
– juanpa.arrivillaga
45 mins ago