how to sum variables from file in bash





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







1















Hello I need to sum numbers from a file line by line.



The file:



1.0

0.46

0.67


I want to sum, then divide 3.



I currently have:



while IFS= read -r var

do

   x=$(($var + $x)) | bc -l

done < "file.txt"

echo "$x / 3"


My error:



-bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")





bash arithmetic







share|improve this question































    1















    Hello I need to sum numbers from a file line by line.



    The file:



    1.0
    
0.46
    
0.67


    I want to sum, then divide 3.



    I currently have:



    while IFS= read -r var
    
do
    
   x=$(($var + $x)) | bc -l
    
done < "file.txt"
    
echo "$x / 3"


    My error:



    -bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")





    bash arithmetic







    share|improve this question



























      1












      1








      1








      Hello I need to sum numbers from a file line by line.



      The file:



      1.0
      
0.46
      
0.67


      I want to sum, then divide 3.



      I currently have:



      while IFS= read -r var
      
do
      
   x=$(($var + $x)) | bc -l
      
done < "file.txt"
      
echo "$x / 3"


      My error:



      -bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")





      bash arithmetic







      share|improve this question
















      Hello I need to sum numbers from a file line by line.



      The file:



      1.0
      
0.46
      
0.67


      I want to sum, then divide 3.



      I currently have:



      while IFS= read -r var
      
do
      
   x=$(($var + $x)) | bc -l
      
done < "file.txt"
      
echo "$x / 3"


      My error:



      -bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")





      bash arithmetic




      bash arithmetic






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago









      Jesse_b

      14.7k33574




      14.7k33574










      asked 2 hours ago









      AhmetMelihBaşbuğAhmetMelihBaşbuğ

      1175




      1175






















          3 Answers
          3






          active

          oldest

          votes


















          3














          bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



          awk '{sum= sum+$1} END {print sum/3}' file


          This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






          share|improve this answer































            1














            Just for fun



            $ paste -sd+ file | dc -e2k0 -f- -e+3/p
            
.71





            share|improve this answer































              0














              Try this:



              x=0
              
while IFS= read -r var; do
              
    x="$(echo "$var + $x" | bc -l)"
              
done < "file.txt"
              
echo "$x / 3" | bc -l




              1. x was not defined.

              2. You need an echo for bc to work (not mixed bash arithmetic).






              share|improve this answer
























                Your Answer








                StackExchange.ready(function() {
                var channelOptions = {
                tags: "".split(" "),
                id: "106"
                };
                initTagRenderer("".split(" "), "".split(" "), channelOptions);

                StackExchange.using("externalEditor", function() {
                // Have to fire editor after snippets, if snippets enabled
                if (StackExchange.settings.snippets.snippetsEnabled) {
                StackExchange.using("snippets", function() {
                createEditor();
                });
                }
                else {
                createEditor();
                }
                });

                function createEditor() {
                StackExchange.prepareEditor({
                heartbeatType: 'answer',
                autoActivateHeartbeat: false,
                convertImagesToLinks: false,
                noModals: true,
                showLowRepImageUploadWarning: true,
                reputationToPostImages: null,
                bindNavPrevention: true,
                postfix: "",
                imageUploader: {
                brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
                contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
                allowUrls: true
                },
                onDemand: true,
                discardSelector: ".discard-answer"
                ,immediatelyShowMarkdownHelp:true
                });


                }
                });














                draft saved

                draft discarded


















                StackExchange.ready(
                function () {
                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f515923%2fhow-to-sum-variables-from-file-in-bash%23new-answer', 'question_page');
                }
                );

                Post as a guest















                Required, but never shown

























                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                3














                bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                awk '{sum= sum+$1} END {print sum/3}' file


                This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






                share|improve this answer




























                  3














                  bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                  awk '{sum= sum+$1} END {print sum/3}' file


                  This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






                  share|improve this answer


























                    3












                    3








                    3







                    bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                    awk '{sum= sum+$1} END {print sum/3}' file


                    This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






                    share|improve this answer













                    bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                    awk '{sum= sum+$1} END {print sum/3}' file


                    This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 2 hours ago









                    Jesse_bJesse_b

                    14.7k33574




                    14.7k33574

























                        1














                        Just for fun



                        $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                        
.71





                        share|improve this answer




























                          1














                          Just for fun



                          $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                          
.71





                          share|improve this answer


























                            1












                            1








                            1







                            Just for fun



                            $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                            
.71





                            share|improve this answer













                            Just for fun



                            $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                            
.71






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 1 hour ago









                            steeldriversteeldriver

                            38.2k45489




                            38.2k45489























                                0














                                Try this:



                                x=0
                                
while IFS= read -r var; do
                                
    x="$(echo "$var + $x" | bc -l)"
                                
done < "file.txt"
                                
echo "$x / 3" | bc -l




                                1. x was not defined.

                                2. You need an echo for bc to work (not mixed bash arithmetic).






                                share|improve this answer




























                                  0














                                  Try this:



                                  x=0
                                  
while IFS= read -r var; do
                                  
    x="$(echo "$var + $x" | bc -l)"
                                  
done < "file.txt"
                                  
echo "$x / 3" | bc -l




                                  1. x was not defined.

                                  2. You need an echo for bc to work (not mixed bash arithmetic).






                                  share|improve this answer


























                                    0












                                    0








                                    0







                                    Try this:



                                    x=0
                                    
while IFS= read -r var; do
                                    
    x="$(echo "$var + $x" | bc -l)"
                                    
done < "file.txt"
                                    
echo "$x / 3" | bc -l




                                    1. x was not defined.

                                    2. You need an echo for bc to work (not mixed bash arithmetic).






                                    share|improve this answer













                                    Try this:



                                    x=0
                                    
while IFS= read -r var; do
                                    
    x="$(echo "$var + $x" | bc -l)"
                                    
done < "file.txt"
                                    
echo "$x / 3" | bc -l




                                    1. x was not defined.

                                    2. You need an echo for bc to work (not mixed bash arithmetic).







                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 1 hour ago









                                    FreddyFreddy

                                    2,241210




                                    2,241210






























                                        draft saved

                                        draft discarded




















































                                        Thanks for contributing an answer to Unix & Linux Stack Exchange!


                                        • Please be sure to answer the question. Provide details and share your research!

                                        But avoid …



                                        • Asking for help, clarification, or responding to other answers.

                                        • Making statements based on opinion; back them up with references or personal experience.


                                        To learn more, see our tips on writing great answers.




                                        draft saved


                                        draft discarded














                                        StackExchange.ready(
                                        function () {
                                        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f515923%2fhow-to-sum-variables-from-file-in-bash%23new-answer', 'question_page');
                                        }
                                        );

                                        Post as a guest















                                        Required, but never shown





















































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown

































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown







                                        -

                                        Popular posts from this blog

                                        What are all the squawk codes?

                                        Image
                                        2 $begingroup$ I love aviation and I love learning new things about it. I was wondering if anyone knew all of the squawk codes and in particular what squawk 7500 means. squawk-codes share | improve this question edited 15 mins ago Jamiec ♦ 14.8k 4 60 91 asked 5 hours ago Zac Callaghan Zac Callaghan 11 2 New contributor Zac Callaghan is a new co
                                        Read more

                                        What are differences between VBoxVGA, VMSVGA and VBoxSVGA in VirtualBox?

                                        Image
                                        1 VirtualBox 6.0 provides a new setting called Graphics Controller. There are four options to choose from: None VBoxVGA VMSVGA VBoxSVGA In the user manual I have found this information: Graphics Controller: Specifies the graphics adapter type used by the guest VM. Note that you must install the Guest Additions on the guest VM to specify the VBoxSVGA or VMSVGA graphics controller. The following options are available: – VBoxSVGA: The default graphics controller for new VMs that use Linux or Windows 7 or later. This graphics controller improves performance and 3D support when compared to the legacy VBoxVGA option. – VBoxVGA: Use this graphics controller for legacy guest OSes. This is the default graphics controller for Windows versions before Windows 7. – VMSVGA: Use this graphics controller to emul
                                        Read more

                                        Hudsonelva

                                        Image
                                        Hudson elv Land   USA Område New York Sideelvar Mohawk Lengd 507 km Middelvassføring 606 m³/s Munning Upper New York Bay i Atlanterhavet Elvene Hudson og Mohawk med nedbørsområdet markert med gult. Wikimedia Commons: Hudson River Hudsonelva ( Hudson River ) mohikansk Muh-he-kun-ne-tuk ) er ei elv i USA. Ho renn hovudsakleg gjennom delstaten New York, men markerer også ein del av grensa mellom New York og New Jersey. Hudsonelva har namn etter Henry Hudson, ein engelskmann som utforska elva i 1609. Hudsonelva sett frå Bear Mountain Bridge. Kjelda til elva er Tear-of-the-Clouds-sjøen i Adirondackfjella. Ved Albany renn Mohawk-elva saman med henne, og deretter renn ho nesten rett sørover til ho munnar ut i Atlanterhavet mellom Manhattan i New York og New Jersey. Eriekanalen, som blei opna den 26 oktober 1825, bind saman Hudsonelva og Eriesjøen, slik at byane ved Dei store sjøane fekk vasstilgang til A
                                        Read more