♦ Series - Getting a free donut
$begingroup$
Introduction
There is a way to get a free donut at a coffee shop near the Stack Exchange offices.
However, you are required to solve a phrase and convert it into a single number.
Codes
You watch as a cashier says:
Do not use the toilets here. We're washing them.
And then the person replies:
$38$.
They get a free donut.
Next, another person walks in and you listen again. The cashier says:
Donuts by the dozen are $3.
The person replies:
$20$.
Once again, the cashier gives the person a free donut.
You go back the following day and watch as more people get their own free donuts.
The cashier says:
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
The person replies:
$20$.
Once again, they get a free donut.
The cashier says to another customer:
Your donuts aren't considered free yet.
The customer replies:
$50$.
This is also correct, and the cashier gives them free donuts.
You go up to the counter and the cashier says:
No donuts right now. We're making some more.
You come up with a random number:
Hmm... $44$?
She replies:
Sorry, but I do not know what you are talking about.
(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)
You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)
Hints
- Hint 1:
Donut ignore the pun in this hint.
- Hint 2:
Do you nut see a tasty treat hidden in this?
- Hint 3:
Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."
- Hint 4:
$6+2+7+2+8+2+9+2+10+2 = 50$.
story password steganography
asked Jul 3 '16 at 2:52
haykamhaykam
904323
$endgroup$
|
show 8 more comments
$begingroup$
Introduction
There is a way to get a free donut at a coffee shop near the Stack Exchange offices.
However, you are required to solve a phrase and convert it into a single number.
Codes
You watch as a cashier says:
Do not use the toilets here. We're washing them.
And then the person replies:
$38$.
They get a free donut.
Next, another person walks in and you listen again. The cashier says:
Donuts by the dozen are $3.
The person replies:
$20$.
Once again, the cashier gives the person a free donut.
You go back the following day and watch as more people get their own free donuts.
The cashier says:
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
The person replies:
$20$.
Once again, they get a free donut.
The cashier says to another customer:
Your donuts aren't considered free yet.
The customer replies:
$50$.
This is also correct, and the cashier gives them free donuts.
You go up to the counter and the cashier says:
No donuts right now. We're making some more.
You come up with a random number:
Hmm... $44$?
She replies:
Sorry, but I do not know what you are talking about.
(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)
You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)
Hints
- Hint 1:
Donut ignore the pun in this hint.
- Hint 2:
Do you nut see a tasty treat hidden in this?
- Hint 3:
Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."
- Hint 4:
$6+2+7+2+8+2+9+2+10+2 = 50$.
story password steganography
asked Jul 3 '16 at 2:52
haykamhaykam
904323
$endgroup$
1
$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58
1
$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01
6
$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40
1
$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25
2
$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now.:)
$endgroup$
– M Oehm
Jul 5 '16 at 5:19
|
show 8 more comments
$begingroup$
Introduction
There is a way to get a free donut at a coffee shop near the Stack Exchange offices.
However, you are required to solve a phrase and convert it into a single number.
Codes
You watch as a cashier says:
Do not use the toilets here. We're washing them.
And then the person replies:
$38$.
They get a free donut.
Next, another person walks in and you listen again. The cashier says:
Donuts by the dozen are $3.
The person replies:
$20$.
Once again, the cashier gives the person a free donut.
You go back the following day and watch as more people get their own free donuts.
The cashier says:
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
The person replies:
$20$.
Once again, they get a free donut.
The cashier says to another customer:
Your donuts aren't considered free yet.
The customer replies:
$50$.
This is also correct, and the cashier gives them free donuts.
You go up to the counter and the cashier says:
No donuts right now. We're making some more.
You come up with a random number:
Hmm... $44$?
She replies:
Sorry, but I do not know what you are talking about.
(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)
You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)
Hints
- Hint 1:
Donut ignore the pun in this hint.
- Hint 2:
Do you nut see a tasty treat hidden in this?
- Hint 3:
Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."
- Hint 4:
$6+2+7+2+8+2+9+2+10+2 = 50$.
story password steganography
asked Jul 3 '16 at 2:52
haykamhaykam
904323
$endgroup$
Introduction
There is a way to get a free donut at a coffee shop near the Stack Exchange offices.
However, you are required to solve a phrase and convert it into a single number.
Codes
You watch as a cashier says:
Do not use the toilets here. We're washing them.
And then the person replies:
$38$.
They get a free donut.
Next, another person walks in and you listen again. The cashier says:
Donuts by the dozen are $3.
The person replies:
$20$.
Once again, the cashier gives the person a free donut.
You go back the following day and watch as more people get their own free donuts.
The cashier says:
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
The person replies:
$20$.
Once again, they get a free donut.
The cashier says to another customer:
Your donuts aren't considered free yet.
The customer replies:
$50$.
This is also correct, and the cashier gives them free donuts.
You go up to the counter and the cashier says:
No donuts right now. We're making some more.
You come up with a random number:
Hmm... $44$?
She replies:
Sorry, but I do not know what you are talking about.
(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)
You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)
Hints
- Hint 1:
Donut ignore the pun in this hint.
- Hint 2:
Do you nut see a tasty treat hidden in this?
- Hint 3:
Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."
- Hint 4:
$6+2+7+2+8+2+9+2+10+2 = 50$.
story password steganography
story password steganography
asked Jul 3 '16 at 2:52
haykamhaykam
904323
asked Jul 3 '16 at 2:52
haykamhaykam
904323
edited 5 mins ago
haykam
asked Jul 3 '16 at 2:52
haykamhaykam
904323
asked Jul 3 '16 at 2:52
haykamhaykam
904323
asked Jul 3 '16 at 2:52
haykamhaykam
904323
904323
1
$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58
1
$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01
6
$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40
1
$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25
2
$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now.:)
$endgroup$
– M Oehm
Jul 5 '16 at 5:19
|
show 8 more comments
1
$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58
1
$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01
6
$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40
1
$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25
2
$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now.:)
$endgroup$
– M Oehm
Jul 5 '16 at 5:19
1
1
$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58
$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58
1
1
$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01
$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01
6
6
$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40
$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40
1
1
$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25
$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25
2
2
$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now.
:)$endgroup$
– M Oehm
Jul 5 '16 at 5:19
$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now.
:)$endgroup$
– M Oehm
Jul 5 '16 at 5:19
|
show 8 more comments
7 Answers
7
active
oldest
votes
$begingroup$
You should have answered
40
to begin with, but now you can answer
149
to get a free donut.
The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.
Do not use the toilets here. We're washing them.
D = First word, first character = 1, 1
O = First word, second character = 1, 2
N = Second word, fourth character (including spaces!) = 2, 4
U = Third word, eighth character = 3, 8
T = Fourth word, twelfth character = 4, 121 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38
Donuts by the dozen are $3.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Your donuts aren't considered free yet.
D = 2, 6
O = 2, 7
N = 2, 8
U = 2, 9
T = 2, 102 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50
No donuts right now. We're making some more.
D = 2, 4
O = 2, 5
N = 2, 6
U = 2, 7
T = 2, 82 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40
So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:
Sorry, but I do not know what you are talking about.
D = 4, 14
O = 4, 15
N = 5, 17
U = 8, 33
T = 10, 394 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149
So now, you may answer with 149 to get your free donut.
Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
D = 7, 23
O = 7, 24
N = 7, 25
U = 7, 26
T = 7, 277 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
$endgroup$
1
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
2
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
5
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
1
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
1
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
|
show 3 more comments
$begingroup$
For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals
the number of letters in the cashier's utterance, plus one
with the proviso that
you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".
In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say
either 34 or 40 (if I've counted right).
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
$endgroup$
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
4
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
add a comment |
$begingroup$
My answer is
38
Reasoning
I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.
The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".
The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.
Do not use the toilets here. We're washing them.
The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.
The cashier utters two distinct sentences and 8 is the genus two shape.
Donuts by the dozen are $3.
The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.
The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Your donuts aren't considered free yet.
The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
No donuts right now. We're making some more.
The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.
The cashier utters two sentences which corresponds to the genus two donut 8.
Also,
This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
$endgroup$
add a comment |
$begingroup$
Seems like the question was edited since I posted my answer. So I've adjusted.
Re: What number should you say when you come back?
35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.
answered Jul 3 '16 at 17:12
fluflu
32115
$endgroup$
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
1
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
add a comment |
$begingroup$
The answer is:
20.
Explanation:
Any answer with "donuts" in it is 20
edited Jul 4 '16 at 1:51
haykam
904323
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
$endgroup$
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
1
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
3
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
2
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
|
show 2 more comments
$begingroup$
Possibly a partial:
It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.
'No donuts right now. We're making some more.':
You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.
'Sorry, but I do not know what you are talking about.'
For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.
Not solved:
The first digit.
Crazy guess:
The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).
Additional from comment on @flu's answer:
'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160
There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.
--
The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
$endgroup$
add a comment |
$begingroup$
58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f36922%2fseries-getting-a-free-donut%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You should have answered
40
to begin with, but now you can answer
149
to get a free donut.
The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.
Do not use the toilets here. We're washing them.
D = First word, first character = 1, 1
O = First word, second character = 1, 2
N = Second word, fourth character (including spaces!) = 2, 4
U = Third word, eighth character = 3, 8
T = Fourth word, twelfth character = 4, 121 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38
Donuts by the dozen are $3.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Your donuts aren't considered free yet.
D = 2, 6
O = 2, 7
N = 2, 8
U = 2, 9
T = 2, 102 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50
No donuts right now. We're making some more.
D = 2, 4
O = 2, 5
N = 2, 6
U = 2, 7
T = 2, 82 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40
So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:
Sorry, but I do not know what you are talking about.
D = 4, 14
O = 4, 15
N = 5, 17
U = 8, 33
T = 10, 394 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149
So now, you may answer with 149 to get your free donut.
Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
D = 7, 23
O = 7, 24
N = 7, 25
U = 7, 26
T = 7, 277 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
$endgroup$
1
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
2
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
5
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
1
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
1
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
|
show 3 more comments
$begingroup$
You should have answered
40
to begin with, but now you can answer
149
to get a free donut.
The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.
Do not use the toilets here. We're washing them.
D = First word, first character = 1, 1
O = First word, second character = 1, 2
N = Second word, fourth character (including spaces!) = 2, 4
U = Third word, eighth character = 3, 8
T = Fourth word, twelfth character = 4, 121 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38
Donuts by the dozen are $3.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Your donuts aren't considered free yet.
D = 2, 6
O = 2, 7
N = 2, 8
U = 2, 9
T = 2, 102 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50
No donuts right now. We're making some more.
D = 2, 4
O = 2, 5
N = 2, 6
U = 2, 7
T = 2, 82 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40
So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:
Sorry, but I do not know what you are talking about.
D = 4, 14
O = 4, 15
N = 5, 17
U = 8, 33
T = 10, 394 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149
So now, you may answer with 149 to get your free donut.
Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
D = 7, 23
O = 7, 24
N = 7, 25
U = 7, 26
T = 7, 277 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
$endgroup$
1
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
2
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
5
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
1
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
1
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
|
show 3 more comments
$begingroup$
You should have answered
40
to begin with, but now you can answer
149
to get a free donut.
The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.
Do not use the toilets here. We're washing them.
D = First word, first character = 1, 1
O = First word, second character = 1, 2
N = Second word, fourth character (including spaces!) = 2, 4
U = Third word, eighth character = 3, 8
T = Fourth word, twelfth character = 4, 121 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38
Donuts by the dozen are $3.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Your donuts aren't considered free yet.
D = 2, 6
O = 2, 7
N = 2, 8
U = 2, 9
T = 2, 102 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50
No donuts right now. We're making some more.
D = 2, 4
O = 2, 5
N = 2, 6
U = 2, 7
T = 2, 82 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40
So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:
Sorry, but I do not know what you are talking about.
D = 4, 14
O = 4, 15
N = 5, 17
U = 8, 33
T = 10, 394 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149
So now, you may answer with 149 to get your free donut.
Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
D = 7, 23
O = 7, 24
N = 7, 25
U = 7, 26
T = 7, 277 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
$endgroup$
You should have answered
40
to begin with, but now you can answer
149
to get a free donut.
The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.
Do not use the toilets here. We're washing them.
D = First word, first character = 1, 1
O = First word, second character = 1, 2
N = Second word, fourth character (including spaces!) = 2, 4
U = Third word, eighth character = 3, 8
T = Fourth word, twelfth character = 4, 121 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38
Donuts by the dozen are $3.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.
D = 1, 1
O = 1, 2
N = 1, 3
U = 1, 4
T = 1, 51 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20
Your donuts aren't considered free yet.
D = 2, 6
O = 2, 7
N = 2, 8
U = 2, 9
T = 2, 102 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50
No donuts right now. We're making some more.
D = 2, 4
O = 2, 5
N = 2, 6
U = 2, 7
T = 2, 82 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40
So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:
Sorry, but I do not know what you are talking about.
D = 4, 14
O = 4, 15
N = 5, 17
U = 8, 33
T = 10, 394 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149
So now, you may answer with 149 to get your free donut.
Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
D = 7, 23
O = 7, 24
N = 7, 25
U = 7, 26
T = 7, 277 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
edited Aug 4 '16 at 19:03
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
answered Aug 3 '16 at 16:25
Morgan GMorgan G
1,801527
1,801527
1
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
2
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
5
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
1
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
1
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
|
show 3 more comments
1
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
2
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
5
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
1
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
1
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
1
1
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
$begingroup$
I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
$endgroup$
– Arth
Aug 3 '16 at 16:34
2
2
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
$begingroup$
@Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
$endgroup$
– Morgan G
Aug 3 '16 at 17:10
5
5
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
$begingroup$
Oh my goodness thank you, @MorganG, for putting this one to rest.
$endgroup$
– Dan Russell
Aug 3 '16 at 17:13
1
1
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
$begingroup$
Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
$endgroup$
– haykam
Aug 3 '16 at 17:17
1
1
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
$begingroup$
@Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
$endgroup$
– Morgan G
Aug 3 '16 at 17:20
|
show 3 more comments
$begingroup$
For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals
the number of letters in the cashier's utterance, plus one
with the proviso that
you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".
In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say
either 34 or 40 (if I've counted right).
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
$endgroup$
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
4
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
add a comment |
$begingroup$
For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals
the number of letters in the cashier's utterance, plus one
with the proviso that
you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".
In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say
either 34 or 40 (if I've counted right).
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
$endgroup$
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
4
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
add a comment |
$begingroup$
For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals
the number of letters in the cashier's utterance, plus one
with the proviso that
you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".
In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say
either 34 or 40 (if I've counted right).
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
$endgroup$
For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals
the number of letters in the cashier's utterance, plus one
with the proviso that
you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".
In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say
either 34 or 40 (if I've counted right).
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
edited Jul 4 '16 at 10:10
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
answered Jul 3 '16 at 3:04
Gareth McCaughan♦Gareth McCaughan
63.5k3163248
63.5k3163248
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
4
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
add a comment |
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
4
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:39
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
$endgroup$
– f''
Jul 4 '16 at 2:16
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
$begingroup$
@f", the rule has stayed the same this whole time.
$endgroup$
– haykam
Jul 4 '16 at 2:24
4
4
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
@Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
$endgroup$
– f''
Jul 4 '16 at 2:30
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
$begingroup$
I hereby confirm that f'' has understood me correctly.
$endgroup$
– Gareth McCaughan♦
Jul 4 '16 at 10:10
add a comment |
$begingroup$
My answer is
38
Reasoning
I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.
The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".
The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.
Do not use the toilets here. We're washing them.
The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.
The cashier utters two distinct sentences and 8 is the genus two shape.
Donuts by the dozen are $3.
The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.
The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Your donuts aren't considered free yet.
The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
No donuts right now. We're making some more.
The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.
The cashier utters two sentences which corresponds to the genus two donut 8.
Also,
This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
$endgroup$
add a comment |
$begingroup$
My answer is
38
Reasoning
I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.
The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".
The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.
Do not use the toilets here. We're washing them.
The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.
The cashier utters two distinct sentences and 8 is the genus two shape.
Donuts by the dozen are $3.
The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.
The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Your donuts aren't considered free yet.
The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
No donuts right now. We're making some more.
The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.
The cashier utters two sentences which corresponds to the genus two donut 8.
Also,
This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
$endgroup$
add a comment |
$begingroup$
My answer is
38
Reasoning
I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.
The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".
The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.
Do not use the toilets here. We're washing them.
The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.
The cashier utters two distinct sentences and 8 is the genus two shape.
Donuts by the dozen are $3.
The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.
The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Your donuts aren't considered free yet.
The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
No donuts right now. We're making some more.
The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.
The cashier utters two sentences which corresponds to the genus two donut 8.
Also,
This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
$endgroup$
My answer is
38
Reasoning
I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.
The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".
The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.
Do not use the toilets here. We're washing them.
The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.
The cashier utters two distinct sentences and 8 is the genus two shape.
Donuts by the dozen are $3.
The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.
The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
Your donuts aren't considered free yet.
The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.
The cashier utters one sentence which corresponds to the simple genus one donut 0.
No donuts right now. We're making some more.
The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.
The cashier utters two sentences which corresponds to the genus two donut 8.
Also,
This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
answered Jul 6 '16 at 10:46
hexominohexomino
41.7k3125198
41.7k3125198
add a comment |
add a comment |
$begingroup$
Seems like the question was edited since I posted my answer. So I've adjusted.
Re: What number should you say when you come back?
35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.
answered Jul 3 '16 at 17:12
fluflu
32115
$endgroup$
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
1
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
add a comment |
$begingroup$
Seems like the question was edited since I posted my answer. So I've adjusted.
Re: What number should you say when you come back?
35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.
answered Jul 3 '16 at 17:12
fluflu
32115
$endgroup$
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
1
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
add a comment |
$begingroup$
Seems like the question was edited since I posted my answer. So I've adjusted.
Re: What number should you say when you come back?
35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.
answered Jul 3 '16 at 17:12
fluflu
32115
$endgroup$
Seems like the question was edited since I posted my answer. So I've adjusted.
Re: What number should you say when you come back?
35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.
answered Jul 3 '16 at 17:12
fluflu
32115
edited Jul 3 '16 at 22:18
answered Jul 3 '16 at 17:12
fluflu
32115
answered Jul 3 '16 at 17:12
fluflu
32115
answered Jul 3 '16 at 17:12
fluflu
32115
32115
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
1
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
add a comment |
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
1
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
$begingroup$
The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
$endgroup$
– haykam
Jul 4 '16 at 1:40
1
1
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
$endgroup$
– HardScale
Jul 4 '16 at 3:47
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
$endgroup$
– mestackoverflow
Jul 4 '16 at 8:09
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
$begingroup$
The resulting number of that message, @ericm301, would be 160.
$endgroup$
– haykam
Jul 5 '16 at 2:19
add a comment |
$begingroup$
The answer is:
20.
Explanation:
Any answer with "donuts" in it is 20
edited Jul 4 '16 at 1:51
haykam
904323
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
$endgroup$
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
1
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
3
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
2
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
|
show 2 more comments
$begingroup$
The answer is:
20.
Explanation:
Any answer with "donuts" in it is 20
edited Jul 4 '16 at 1:51
haykam
904323
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
$endgroup$
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
1
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
3
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
2
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
|
show 2 more comments
$begingroup$
The answer is:
20.
Explanation:
Any answer with "donuts" in it is 20
edited Jul 4 '16 at 1:51
haykam
904323
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
$endgroup$
The answer is:
20.
Explanation:
Any answer with "donuts" in it is 20
edited Jul 4 '16 at 1:51
haykam
904323
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
edited Jul 4 '16 at 1:51
haykam
904323
edited Jul 4 '16 at 1:51
haykam
904323
edited Jul 4 '16 at 1:51
haykam
904323
904323
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
answered Jul 4 '16 at 1:41
AreebAreeb
1,3781726
1,3781726
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
1
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
3
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
2
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
|
show 2 more comments
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
1
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
3
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
2
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
$begingroup$
This is not the answer I was looking for, nor is it a complete answer.
$endgroup$
– haykam
Jul 4 '16 at 1:44
1
1
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I knew it was too simple, why doesn't 20 work?
$endgroup$
– Areeb
Jul 4 '16 at 1:53
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
$begingroup$
I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
$endgroup$
– haykam
Jul 4 '16 at 2:01
3
3
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
$begingroup$
This fits all the current clues.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:02
2
2
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
$begingroup$
@Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
$endgroup$
– Dan Russell
Jul 4 '16 at 2:05
|
show 2 more comments
$begingroup$
Possibly a partial:
It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.
'No donuts right now. We're making some more.':
You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.
'Sorry, but I do not know what you are talking about.'
For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.
Not solved:
The first digit.
Crazy guess:
The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).
Additional from comment on @flu's answer:
'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160
There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.
--
The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
$endgroup$
add a comment |
$begingroup$
Possibly a partial:
It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.
'No donuts right now. We're making some more.':
You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.
'Sorry, but I do not know what you are talking about.'
For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.
Not solved:
The first digit.
Crazy guess:
The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).
Additional from comment on @flu's answer:
'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160
There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.
--
The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
$endgroup$
add a comment |
$begingroup$
Possibly a partial:
It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.
'No donuts right now. We're making some more.':
You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.
'Sorry, but I do not know what you are talking about.'
For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.
Not solved:
The first digit.
Crazy guess:
The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).
Additional from comment on @flu's answer:
'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160
There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.
--
The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
$endgroup$
Possibly a partial:
It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.
'No donuts right now. We're making some more.':
You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.
'Sorry, but I do not know what you are talking about.'
For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.
Not solved:
The first digit.
Crazy guess:
The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).
Additional from comment on @flu's answer:
'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160
There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.
--
The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
edited Jul 6 '16 at 14:53
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
answered Jul 6 '16 at 12:25
ArthArth
3,1901331
3,1901331
add a comment |
add a comment |
$begingroup$
58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
$endgroup$
add a comment |
$begingroup$
58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
$endgroup$
add a comment |
$begingroup$
58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
$endgroup$
58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
edited Aug 2 '16 at 1:37
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
answered Aug 2 '16 at 1:28
Ray WuRay Wu
697
697
add a comment |
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f36922%2fseries-getting-a-free-donut%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58
1
$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01
6
$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40
1
$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25
2
$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now.
:)$endgroup$
– M Oehm
Jul 5 '16 at 5:19