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Previously a member @Evan Chen, wrote this script :

#!/bin/bash

while [ true ] 

do

    currentoutput="$(lsusb)"

    if [ "$currentoutput" != "$lastoutput" ]

    then

        echo "" date and Time >> test.log

        date +%x_r >> test.log

        lastoutput="$(lsusb)"

        lsusb >> test.log

    fi

    sleep 5

done

I'm a newbie, trying to learn fast and I got a question about the variable's quotation marks.

Put a variable between $(), I get it, but why the quotation marks are needed, even in the if statement ?

To make a nested command ??

Thanks

In currentoutput="$(lsusb)" lsusb is not a variable, it is a command. What this statement does, it executes lsusb command and assigns its output to currentoutput variable.

Older syntax for this was

currentoutput=`lsusb`

you can find it in many examples and scripts

To answer the other part of your question, if [ ] is just how syntax for if is defined in bash. See more in https://www.tldp.org/LDP/Bash-Beginners-Guide/html/sect_07_01.html

The following runs the external command command and returns its output.

"$(command)"

Without the brackets/parentheses, this would look for a variable instead of running a command:

"$variable"

As for the difference between $variable and "$variable", this becomes relevant when $variable contains spaces. When using "$variable", the entire variable contents will be inserted into a single string even if the contents include spaces. When using $variable the contents of the variable may be expanded into an argument list of multiple arguments.

Quotation marks prevent word splitting - that is breaking down variables into multiple items at whitespaces (or to be more exact, at spaces, tabs, and newlines as defined in default value of $IFS shell variable).

For example,

$ var="one two"

$ howmany(){ echo $#;  }

$ howmany $var

2

$ howmany "$var"

1

Here we define howmany function which just lets us know how many positional parameters are given. As you can see, there are two items being passed to the variable, and with the quotes the text in the variable is treated as one unit.

This is important for accurate passing of information. For example, if the variable contains path to file, and the filename contains spaces anywhere in the path, the command you are trying to run may fail or give inaccurate result. If we were trying to create file with $var variable, touch $var would create two files, but touch "$var" just one.

Assigning command substitution doesn't require double quotes as in

var=$( df )

where you have df command's output saved to var. However, it is a good habit to always double quote variables and command substitution $(...) unless you do in fact want the output to be treated as separate items.

On side note, the

while [ true ]

part can be

while true

[ is a command which evaluates its arguments, and [ whatever ] is always true regardless of what is inside. By contrast, while true uses the command true which always returns success exit status (and that's exactly what while loop needs). The difference is a bit more clarity and less testing performed. Alternatively, you could also use : instead of true

The double quotes echo "" date and Time part could probably be removed. They merely insert empty string and add extra space to the output. If that's desired, feel free to keep them there, but there's no particular functional value in this case.

lsusb >> test.log

This part could probably be replaced with echo "$currentoutput" >> test.log. There's no reason to run lsusb again after it has been ran already in currentoutput=$(lsusb). In cases where trailing newlines
have to be preserved in the output - one could see the value in running a command multiple times, but in case of lsusb there's no need for that. The less external commands you call, the better, because every call to a non-built-in command costs in CPU, memory usage, and execution time ( even though the commands are probably pre-loaded from memory).

See also:

• When is double-quoting necessary?


• What is the point of the bash null operator : (colon)?