RegionDifference for Cylinder and Cuboid












4












$begingroup$


I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];

reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];

Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try 



reg = RegionDifference[reg1, reg2];

Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.






regions







share|improve this question









$endgroup$








  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    2 hours ago








  • 1




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    1 hour ago
















4












$begingroup$


I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];

reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];

Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try 



reg = RegionDifference[reg1, reg2];

Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.






regions







share|improve this question









$endgroup$








  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    2 hours ago








  • 1




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    1 hour ago














4












4








4





$begingroup$


I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];

reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];

Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try 



reg = RegionDifference[reg1, reg2];

Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.






regions







share|improve this question









$endgroup$




I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];

reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];

Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try 



reg = RegionDifference[reg1, reg2];

Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.






regions




regions






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 2 hours ago









HughHugh

6,47921945




6,47921945








  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    2 hours ago








  • 1




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    1 hour ago














  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    2 hours ago








  • 1




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    1 hour ago








1




1




$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
$endgroup$
– Henrik Schumacher
2 hours ago






$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
$endgroup$
– Henrik Schumacher
2 hours ago






1




1




$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
1 hour ago




$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
1 hour ago










2 Answers
2






active

oldest

votes


















4












$begingroup$

Please note the RegionBounds:



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];

reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];

reg = RegionDifference[reg1, reg2];



bounds = RegionBounds@reg;

Region[reg, Axes -> True, PlotRange -> bounds]


enter image description here






share|improve this answer









$endgroup$





















    2












    $begingroup$

    This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



    reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
    
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
    
reg = RegionDifference[reg1, reg2]


    enter image description here



    As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






    share|improve this answer











    $endgroup$













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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

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      active

      oldest

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      active

      oldest

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      4












      $begingroup$

      Please note the RegionBounds:



      reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
      
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
      
reg = RegionDifference[reg1, reg2];
      

      
bounds = RegionBounds@reg;
      
Region[reg, Axes -> True, PlotRange -> bounds]


      enter image description here






      share|improve this answer









      $endgroup$


















        4












        $begingroup$

        Please note the RegionBounds:



        reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
        
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
        
reg = RegionDifference[reg1, reg2];
        

        
bounds = RegionBounds@reg;
        
Region[reg, Axes -> True, PlotRange -> bounds]


        enter image description here






        share|improve this answer









        $endgroup$
















          4












          4








          4





          $begingroup$

          Please note the RegionBounds:



          reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
          
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
          
reg = RegionDifference[reg1, reg2];
          

          
bounds = RegionBounds@reg;
          
Region[reg, Axes -> True, PlotRange -> bounds]


          enter image description here






          share|improve this answer









          $endgroup$



          Please note the RegionBounds:



          reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
          
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
          
reg = RegionDifference[reg1, reg2];
          

          
bounds = RegionBounds@reg;
          
Region[reg, Axes -> True, PlotRange -> bounds]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 47 mins ago









          rmwrmw

          3297




          3297























              2












              $begingroup$

              This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



              reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
              
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
              
reg = RegionDifference[reg1, reg2]


              enter image description here



              As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






              share|improve this answer











              $endgroup$


















                2












                $begingroup$

                This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



                reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
                
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
                
reg = RegionDifference[reg1, reg2]


                enter image description here



                As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






                share|improve this answer











                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



                  reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
                  
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
                  
reg = RegionDifference[reg1, reg2]


                  enter image description here



                  As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






                  share|improve this answer











                  $endgroup$



                  This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



                  reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
                  
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
                  
reg = RegionDifference[reg1, reg2]


                  enter image description here



                  As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 23 mins ago









                  Jason B.

                  48.6k388196




                  48.6k388196










                  answered 1 hour ago









                  Henrik SchumacherHenrik Schumacher

                  56.3k577156




                  56.3k577156






























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