Pattern recognition problem: if $2 star 8 star 8 = 161642dots$ then M=?
$begingroup$
The following sequence was given to me:
$$color{red}{2 star 8 star 8 = 161642}$$
$$color{blue}{4 star 9 star 7 = 362843}$$
$$color{red}{7 star 5 star 9 = 356344}$$
$$color{blue}{9 star 6 star 8 = 547245}$$
$$color{red}{5 star 7 star 9 = 354546}$$
$$color{blue}{3 star 9 star 9 = 272748}$$
$$color{red}{4 star 8 star 9 = text{M}}$$
$color{red}{text{M}}$ = ?
My Thoughts:
The first two digits of R.H.S can be found by $a.b$ , where L.H.S = $a star b star c$ ,
i.e, For 1st relation: $2.8=16 = 1^{st}$ two digits of $color{green}{16}1642$
Similarly,the second two digits of R.H.S can be found by $a.c$ , where L.H.S = $a star b star c$ ,
i.e, For 2nd relation: $4.7=28 = 2^{nd} $ two digits of $36 color{green}{28}43$
$$implies M= 3236 , _ , _$$
How do I find the $3^{rd}$ two digits of R.H.S?
logical-deduction pattern
edited 2 mins ago
JonMark Perry
19.8k64095
asked 34 mins ago
SureshSuresh
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$begingroup$
The following sequence was given to me:
$$color{red}{2 star 8 star 8 = 161642}$$
$$color{blue}{4 star 9 star 7 = 362843}$$
$$color{red}{7 star 5 star 9 = 356344}$$
$$color{blue}{9 star 6 star 8 = 547245}$$
$$color{red}{5 star 7 star 9 = 354546}$$
$$color{blue}{3 star 9 star 9 = 272748}$$
$$color{red}{4 star 8 star 9 = text{M}}$$
$color{red}{text{M}}$ = ?
My Thoughts:
The first two digits of R.H.S can be found by $a.b$ , where L.H.S = $a star b star c$ ,
i.e, For 1st relation: $2.8=16 = 1^{st}$ two digits of $color{green}{16}1642$
Similarly,the second two digits of R.H.S can be found by $a.c$ , where L.H.S = $a star b star c$ ,
i.e, For 2nd relation: $4.7=28 = 2^{nd} $ two digits of $36 color{green}{28}43$
$$implies M= 3236 , _ , _$$
How do I find the $3^{rd}$ two digits of R.H.S?
logical-deduction pattern
edited 2 mins ago
JonMark Perry
19.8k64095
asked 34 mins ago
SureshSuresh
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
The following sequence was given to me:
$$color{red}{2 star 8 star 8 = 161642}$$
$$color{blue}{4 star 9 star 7 = 362843}$$
$$color{red}{7 star 5 star 9 = 356344}$$
$$color{blue}{9 star 6 star 8 = 547245}$$
$$color{red}{5 star 7 star 9 = 354546}$$
$$color{blue}{3 star 9 star 9 = 272748}$$
$$color{red}{4 star 8 star 9 = text{M}}$$
$color{red}{text{M}}$ = ?
My Thoughts:
The first two digits of R.H.S can be found by $a.b$ , where L.H.S = $a star b star c$ ,
i.e, For 1st relation: $2.8=16 = 1^{st}$ two digits of $color{green}{16}1642$
Similarly,the second two digits of R.H.S can be found by $a.c$ , where L.H.S = $a star b star c$ ,
i.e, For 2nd relation: $4.7=28 = 2^{nd} $ two digits of $36 color{green}{28}43$
$$implies M= 3236 , _ , _$$
How do I find the $3^{rd}$ two digits of R.H.S?
logical-deduction pattern
edited 2 mins ago
JonMark Perry
19.8k64095
asked 34 mins ago
SureshSuresh
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
The following sequence was given to me:
$$color{red}{2 star 8 star 8 = 161642}$$
$$color{blue}{4 star 9 star 7 = 362843}$$
$$color{red}{7 star 5 star 9 = 356344}$$
$$color{blue}{9 star 6 star 8 = 547245}$$
$$color{red}{5 star 7 star 9 = 354546}$$
$$color{blue}{3 star 9 star 9 = 272748}$$
$$color{red}{4 star 8 star 9 = text{M}}$$
$color{red}{text{M}}$ = ?
My Thoughts:
The first two digits of R.H.S can be found by $a.b$ , where L.H.S = $a star b star c$ ,
i.e, For 1st relation: $2.8=16 = 1^{st}$ two digits of $color{green}{16}1642$
Similarly,the second two digits of R.H.S can be found by $a.c$ , where L.H.S = $a star b star c$ ,
i.e, For 2nd relation: $4.7=28 = 2^{nd} $ two digits of $36 color{green}{28}43$
$$implies M= 3236 , _ , _$$
How do I find the $3^{rd}$ two digits of R.H.S?
logical-deduction pattern
logical-deduction pattern
edited 2 mins ago
JonMark Perry
19.8k64095
asked 34 mins ago
SureshSuresh
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 mins ago
JonMark Perry
19.8k64095
asked 34 mins ago
SureshSuresh
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 2 mins ago
JonMark Perry
19.8k64095
edited 2 mins ago
JonMark Perry
19.8k64095
edited 2 mins ago
JonMark Perry
19.8k64095
19.8k64095
asked 34 mins ago
SureshSuresh
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 34 mins ago
SureshSuresh
1134
asked 34 mins ago
SureshSuresh
1134
1134
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Suresh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
1 Answer
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$begingroup$
M=
$323647$
because
the first four digits are as you gave. The fifth digit is $4$. The final digit is $1$+the lowest digit in the opening local sequence that hasn't already been used by the previous entries in the global sequence. In this case $2+1=3,3+1=4$ and $4+1=5$ have already been used previously, leaving $6+1=7$ as the last digit.
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
$endgroup$
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1 Answer
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1 Answer
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active
oldest
votes
$begingroup$
M=
$323647$
because
the first four digits are as you gave. The fifth digit is $4$. The final digit is $1$+the lowest digit in the opening local sequence that hasn't already been used by the previous entries in the global sequence. In this case $2+1=3,3+1=4$ and $4+1=5$ have already been used previously, leaving $6+1=7$ as the last digit.
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
$endgroup$
add a comment |
$begingroup$
M=
$323647$
because
the first four digits are as you gave. The fifth digit is $4$. The final digit is $1$+the lowest digit in the opening local sequence that hasn't already been used by the previous entries in the global sequence. In this case $2+1=3,3+1=4$ and $4+1=5$ have already been used previously, leaving $6+1=7$ as the last digit.
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
$endgroup$
add a comment |
$begingroup$
M=
$323647$
because
the first four digits are as you gave. The fifth digit is $4$. The final digit is $1$+the lowest digit in the opening local sequence that hasn't already been used by the previous entries in the global sequence. In this case $2+1=3,3+1=4$ and $4+1=5$ have already been used previously, leaving $6+1=7$ as the last digit.
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
$endgroup$
M=
$323647$
because
the first four digits are as you gave. The fifth digit is $4$. The final digit is $1$+the lowest digit in the opening local sequence that hasn't already been used by the previous entries in the global sequence. In this case $2+1=3,3+1=4$ and $4+1=5$ have already been used previously, leaving $6+1=7$ as the last digit.
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
answered 6 mins ago
JonMark PerryJonMark Perry
19.8k64095
19.8k64095
add a comment |
add a comment |
Suresh is a new contributor. Be nice, and check out our Code of Conduct.
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