Why boldmath fails in a tikz node?
7
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
asked 4 hours ago
RmanoRmano
8,34121649
add a comment |
7
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
asked 4 hours ago
RmanoRmano
8,34121649
5
boldmathis not deprecated.
– David Carlisle
3 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the;and the full definition ofboldmathis rather complicated so perhaps it is too much....
– David Carlisle
3 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
27 mins ago
Not only unofficial it is completely wrong.
– David Carlisle
19 mins ago
add a comment |
7
7
7
0
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
asked 4 hours ago
RmanoRmano
8,34121649
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
tikz-pgf boldmath
asked 4 hours ago
RmanoRmano
8,34121649
asked 4 hours ago
RmanoRmano
8,34121649
asked 4 hours ago
RmanoRmano
8,34121649
asked 4 hours ago
RmanoRmano
8,34121649
asked 4 hours ago
RmanoRmano
8,34121649
8,34121649
5
boldmathis not deprecated.
– David Carlisle
3 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the;and the full definition ofboldmathis rather complicated so perhaps it is too much....
– David Carlisle
3 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
27 mins ago
Not only unofficial it is completely wrong.
– David Carlisle
19 mins ago
add a comment |
5
boldmathis not deprecated.
– David Carlisle
3 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the;and the full definition ofboldmathis rather complicated so perhaps it is too much....
– David Carlisle
3 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
27 mins ago
Not only unofficial it is completely wrong.
– David Carlisle
19 mins ago
5
5
boldmath is not deprecated.– David Carlisle
3 hours ago
boldmath is not deprecated.– David Carlisle
3 hours ago
4
4
I seem to recall that tikz only allows a certain number of expansions while looking for the
; and the full definition of boldmath is rather complicated so perhaps it is too much....– David Carlisle
3 hours ago
I seem to recall that tikz only allows a certain number of expansions while looking for the
; and the full definition of boldmath is rather complicated so perhaps it is too much....– David Carlisle
3 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
27 mins ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
27 mins ago
Not only unofficial it is completely wrong.
– David Carlisle
19 mins ago
Not only unofficial it is completely wrong.
– David Carlisle
19 mins ago
add a comment |
1 Answer
1
active
oldest
votes
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 2 hours ago
marmotmarmot
121k6159297
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 2 hours ago
marmotmarmot
121k6159297
add a comment |
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 2 hours ago
marmotmarmot
121k6159297
add a comment |
4
4
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 2 hours ago
marmotmarmot
121k6159297
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 2 hours ago
marmotmarmot
121k6159297
answered 2 hours ago
marmotmarmot
121k6159297
answered 2 hours ago
marmotmarmot
121k6159297
answered 2 hours ago
marmotmarmot
121k6159297
121k6159297
add a comment |
add a comment |
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5
boldmathis not deprecated.– David Carlisle
3 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the
;and the full definition ofboldmathis rather complicated so perhaps it is too much....– David Carlisle
3 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
27 mins ago
Not only unofficial it is completely wrong.
– David Carlisle
19 mins ago