What's Bob's age again?
$begingroup$
I created this problem myself, but I did have inspiration.
Today is a special day, I'm moving out of my parent's house. My father comes to me and says "Wow, you're half my age. On the day we moved into this house, I was four times your age, and your brother Bob was 3 years old." To which I reply "Good times. I remember the day when I almost burned the house down, you were three times my age, and I was twice as old as Bob."
My father then asks "How old is Bob anyway?" We think about it a minute and then my father's eyes bulge out "Bob can't be 27! I am not losing my mind, am I?"
"No", I reply, "Of course Bob is younger than 27. Actually, he is the youngest he can be given what we've already said". How old is Bob?
A useless hint:
As by convention, a person is said to be X years old, if he has lived at least X years, but has not yet lived X+1 years. A person's age is an integer. If I say someone is three times my age, and my age is X, then their age is 3X.
mathematics calculation-puzzle
asked 4 mins ago
AmorydaiAmorydai
79312
$endgroup$
add a comment |
$begingroup$
I created this problem myself, but I did have inspiration.
Today is a special day, I'm moving out of my parent's house. My father comes to me and says "Wow, you're half my age. On the day we moved into this house, I was four times your age, and your brother Bob was 3 years old." To which I reply "Good times. I remember the day when I almost burned the house down, you were three times my age, and I was twice as old as Bob."
My father then asks "How old is Bob anyway?" We think about it a minute and then my father's eyes bulge out "Bob can't be 27! I am not losing my mind, am I?"
"No", I reply, "Of course Bob is younger than 27. Actually, he is the youngest he can be given what we've already said". How old is Bob?
A useless hint:
As by convention, a person is said to be X years old, if he has lived at least X years, but has not yet lived X+1 years. A person's age is an integer. If I say someone is three times my age, and my age is X, then their age is 3X.
mathematics calculation-puzzle
asked 4 mins ago
AmorydaiAmorydai
79312
$endgroup$
add a comment |
$begingroup$
I created this problem myself, but I did have inspiration.
Today is a special day, I'm moving out of my parent's house. My father comes to me and says "Wow, you're half my age. On the day we moved into this house, I was four times your age, and your brother Bob was 3 years old." To which I reply "Good times. I remember the day when I almost burned the house down, you were three times my age, and I was twice as old as Bob."
My father then asks "How old is Bob anyway?" We think about it a minute and then my father's eyes bulge out "Bob can't be 27! I am not losing my mind, am I?"
"No", I reply, "Of course Bob is younger than 27. Actually, he is the youngest he can be given what we've already said". How old is Bob?
A useless hint:
As by convention, a person is said to be X years old, if he has lived at least X years, but has not yet lived X+1 years. A person's age is an integer. If I say someone is three times my age, and my age is X, then their age is 3X.
mathematics calculation-puzzle
asked 4 mins ago
AmorydaiAmorydai
79312
$endgroup$
I created this problem myself, but I did have inspiration.
Today is a special day, I'm moving out of my parent's house. My father comes to me and says "Wow, you're half my age. On the day we moved into this house, I was four times your age, and your brother Bob was 3 years old." To which I reply "Good times. I remember the day when I almost burned the house down, you were three times my age, and I was twice as old as Bob."
My father then asks "How old is Bob anyway?" We think about it a minute and then my father's eyes bulge out "Bob can't be 27! I am not losing my mind, am I?"
"No", I reply, "Of course Bob is younger than 27. Actually, he is the youngest he can be given what we've already said". How old is Bob?
A useless hint:
As by convention, a person is said to be X years old, if he has lived at least X years, but has not yet lived X+1 years. A person's age is an integer. If I say someone is three times my age, and my age is X, then their age is 3X.
mathematics calculation-puzzle
mathematics calculation-puzzle
asked 4 mins ago
AmorydaiAmorydai
79312
asked 4 mins ago
AmorydaiAmorydai
79312
asked 4 mins ago
AmorydaiAmorydai
79312
asked 4 mins ago
AmorydaiAmorydai
79312
asked 4 mins ago
AmorydaiAmorydai
79312
79312
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f80375%2fwhats-bobs-age-again%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f80375%2fwhats-bobs-age-again%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
