Formatting a table to look nice












3












$begingroup$


my current code is:



binsize = 21;
data = {535, 481, 554, 567, 565, 513, 526, 506, 565, 475, 552, 533,
474, 556, 520, 508, 597, 479, 537, 499, 546, 473, 579, 526, 594,
477, 518, 538, 497, 565};
firstbin = 472;
a = BinCounts[data, {firstbin, Max[data] + binsize, binsize}];
b = Range[firstbin, Max[data] + binsize, binsize];
Transpose[{Take[b, Length[a]], a}] // TableForm


Which does give me a nice table, however I would like the bins to be labeled something like "472-492 6" instead of just "472 6"



any advice would be great, thank you.










share|improve this question











$endgroup$

















    3












    $begingroup$


    my current code is:



    binsize = 21;
    data = {535, 481, 554, 567, 565, 513, 526, 506, 565, 475, 552, 533,
    474, 556, 520, 508, 597, 479, 537, 499, 546, 473, 579, 526, 594,
    477, 518, 538, 497, 565};
    firstbin = 472;
    a = BinCounts[data, {firstbin, Max[data] + binsize, binsize}];
    b = Range[firstbin, Max[data] + binsize, binsize];
    Transpose[{Take[b, Length[a]], a}] // TableForm


    Which does give me a nice table, however I would like the bins to be labeled something like "472-492 6" instead of just "472 6"



    any advice would be great, thank you.










    share|improve this question











    $endgroup$















      3












      3








      3


      1



      $begingroup$


      my current code is:



      binsize = 21;
      data = {535, 481, 554, 567, 565, 513, 526, 506, 565, 475, 552, 533,
      474, 556, 520, 508, 597, 479, 537, 499, 546, 473, 579, 526, 594,
      477, 518, 538, 497, 565};
      firstbin = 472;
      a = BinCounts[data, {firstbin, Max[data] + binsize, binsize}];
      b = Range[firstbin, Max[data] + binsize, binsize];
      Transpose[{Take[b, Length[a]], a}] // TableForm


      Which does give me a nice table, however I would like the bins to be labeled something like "472-492 6" instead of just "472 6"



      any advice would be great, thank you.










      share|improve this question











      $endgroup$




      my current code is:



      binsize = 21;
      data = {535, 481, 554, 567, 565, 513, 526, 506, 565, 475, 552, 533,
      474, 556, 520, 508, 597, 479, 537, 499, 546, 473, 579, 526, 594,
      477, 518, 538, 497, 565};
      firstbin = 472;
      a = BinCounts[data, {firstbin, Max[data] + binsize, binsize}];
      b = Range[firstbin, Max[data] + binsize, binsize];
      Transpose[{Take[b, Length[a]], a}] // TableForm


      Which does give me a nice table, however I would like the bins to be labeled something like "472-492 6" instead of just "472 6"



      any advice would be great, thank you.







      table formatting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago







      Wombles

















      asked 2 hours ago









      WomblesWombles

      334




      334






















          2 Answers
          2






          active

          oldest

          votes


















          4












          $begingroup$

          {binlims, bincounts} = HistogramList[data, {firstbin, Max[data] + binsize, binsize}];
          bins = Row[{#, #2 - 1}, "-"] & @@@ Partition[binlims, 2, 1];
          TableForm[Transpose[{bins, bincounts}]]


          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very much!
            $endgroup$
            – Wombles
            1 hour ago










          • $begingroup$
            @Wombles, you are welcome.
            $endgroup$
            – kglr
            1 hour ago



















          1












          $begingroup$

          Here is one way:



          bb = b - 1;
          c = Complement[bb, {Min[bb]}];
          Transpose[{Take[b, Length[a]], ConstantArray["---", Length[a]], c, a}] // TableForm


          Here is the output:



          enter image description here






          share|improve this answer











          $endgroup$













          • $begingroup$
            I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
            $endgroup$
            – mjw
            1 hour ago










          • $begingroup$
            You might want ToString and StringJoin
            $endgroup$
            – MarcoB
            1 hour ago











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          2 Answers
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          2 Answers
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          active

          oldest

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          active

          oldest

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          active

          oldest

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          4












          $begingroup$

          {binlims, bincounts} = HistogramList[data, {firstbin, Max[data] + binsize, binsize}];
          bins = Row[{#, #2 - 1}, "-"] & @@@ Partition[binlims, 2, 1];
          TableForm[Transpose[{bins, bincounts}]]


          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very much!
            $endgroup$
            – Wombles
            1 hour ago










          • $begingroup$
            @Wombles, you are welcome.
            $endgroup$
            – kglr
            1 hour ago
















          4












          $begingroup$

          {binlims, bincounts} = HistogramList[data, {firstbin, Max[data] + binsize, binsize}];
          bins = Row[{#, #2 - 1}, "-"] & @@@ Partition[binlims, 2, 1];
          TableForm[Transpose[{bins, bincounts}]]


          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very much!
            $endgroup$
            – Wombles
            1 hour ago










          • $begingroup$
            @Wombles, you are welcome.
            $endgroup$
            – kglr
            1 hour ago














          4












          4








          4





          $begingroup$

          {binlims, bincounts} = HistogramList[data, {firstbin, Max[data] + binsize, binsize}];
          bins = Row[{#, #2 - 1}, "-"] & @@@ Partition[binlims, 2, 1];
          TableForm[Transpose[{bins, bincounts}]]


          enter image description here






          share|improve this answer









          $endgroup$



          {binlims, bincounts} = HistogramList[data, {firstbin, Max[data] + binsize, binsize}];
          bins = Row[{#, #2 - 1}, "-"] & @@@ Partition[binlims, 2, 1];
          TableForm[Transpose[{bins, bincounts}]]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 1 hour ago









          kglrkglr

          187k10203421




          187k10203421












          • $begingroup$
            Thank you very much!
            $endgroup$
            – Wombles
            1 hour ago










          • $begingroup$
            @Wombles, you are welcome.
            $endgroup$
            – kglr
            1 hour ago


















          • $begingroup$
            Thank you very much!
            $endgroup$
            – Wombles
            1 hour ago










          • $begingroup$
            @Wombles, you are welcome.
            $endgroup$
            – kglr
            1 hour ago
















          $begingroup$
          Thank you very much!
          $endgroup$
          – Wombles
          1 hour ago




          $begingroup$
          Thank you very much!
          $endgroup$
          – Wombles
          1 hour ago












          $begingroup$
          @Wombles, you are welcome.
          $endgroup$
          – kglr
          1 hour ago




          $begingroup$
          @Wombles, you are welcome.
          $endgroup$
          – kglr
          1 hour ago











          1












          $begingroup$

          Here is one way:



          bb = b - 1;
          c = Complement[bb, {Min[bb]}];
          Transpose[{Take[b, Length[a]], ConstantArray["---", Length[a]], c, a}] // TableForm


          Here is the output:



          enter image description here






          share|improve this answer











          $endgroup$













          • $begingroup$
            I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
            $endgroup$
            – mjw
            1 hour ago










          • $begingroup$
            You might want ToString and StringJoin
            $endgroup$
            – MarcoB
            1 hour ago
















          1












          $begingroup$

          Here is one way:



          bb = b - 1;
          c = Complement[bb, {Min[bb]}];
          Transpose[{Take[b, Length[a]], ConstantArray["---", Length[a]], c, a}] // TableForm


          Here is the output:



          enter image description here






          share|improve this answer











          $endgroup$













          • $begingroup$
            I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
            $endgroup$
            – mjw
            1 hour ago










          • $begingroup$
            You might want ToString and StringJoin
            $endgroup$
            – MarcoB
            1 hour ago














          1












          1








          1





          $begingroup$

          Here is one way:



          bb = b - 1;
          c = Complement[bb, {Min[bb]}];
          Transpose[{Take[b, Length[a]], ConstantArray["---", Length[a]], c, a}] // TableForm


          Here is the output:



          enter image description here






          share|improve this answer











          $endgroup$



          Here is one way:



          bb = b - 1;
          c = Complement[bb, {Min[bb]}];
          Transpose[{Take[b, Length[a]], ConstantArray["---", Length[a]], c, a}] // TableForm


          Here is the output:



          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 1 hour ago

























          answered 1 hour ago









          mjwmjw

          4228




          4228












          • $begingroup$
            I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
            $endgroup$
            – mjw
            1 hour ago










          • $begingroup$
            You might want ToString and StringJoin
            $endgroup$
            – MarcoB
            1 hour ago


















          • $begingroup$
            I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
            $endgroup$
            – mjw
            1 hour ago










          • $begingroup$
            You might want ToString and StringJoin
            $endgroup$
            – MarcoB
            1 hour ago
















          $begingroup$
          I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
          $endgroup$
          – mjw
          1 hour ago




          $begingroup$
          I wish I knew more about string manipulation to get the first three columns to combine to one column of text!
          $endgroup$
          – mjw
          1 hour ago












          $begingroup$
          You might want ToString and StringJoin
          $endgroup$
          – MarcoB
          1 hour ago




          $begingroup$
          You might want ToString and StringJoin
          $endgroup$
          – MarcoB
          1 hour ago


















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