Why is lead(II) present in two groups of cation analysis?












2












$begingroup$


Well, I found that lead cation $ce{Pb^2+}$ is present in both group 1 and group 2 of cation analysis. But why?






inorganic-chemistry analytical-chemistry







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    2












    $begingroup$


    Well, I found that lead cation $ce{Pb^2+}$ is present in both group 1 and group 2 of cation analysis. But why?






    inorganic-chemistry analytical-chemistry







    share|improve this question











    $endgroup$















      2












      2








      2





      $begingroup$


      Well, I found that lead cation $ce{Pb^2+}$ is present in both group 1 and group 2 of cation analysis. But why?






      inorganic-chemistry analytical-chemistry







      share|improve this question











      $endgroup$




      Well, I found that lead cation $ce{Pb^2+}$ is present in both group 1 and group 2 of cation analysis. But why?






      inorganic-chemistry analytical-chemistry




      inorganic-chemistry analytical-chemistry






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago









      andselisk

      15.3k649109




      15.3k649109










      asked 2 hours ago









      GarimaGarima

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          $begingroup$

          Simply because lead(II) fits both analytical groups:




          • it forms lead(II) chloride $ce{PbCl2}$, a poor soluble chloride, which puts it in the 1st group;

          • it also forms lead(II) sulfide $ce{PbS}$, insoluble in water and diluted acids, which also puts it in the 2nd group.


          One reason for putting lead in both groups is that the chloride is somewhat of a borderline case in terms of being insoluble enough to appear in Group I. Group II represents a more complicated analysis but is more sensitive for lead.






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
            $endgroup$
            – Oscar Lanzi
            58 mins ago






          • 1




            $begingroup$
            @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
            $endgroup$
            – andselisk
            56 mins ago











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          $begingroup$

          Simply because lead(II) fits both analytical groups:




          • it forms lead(II) chloride $ce{PbCl2}$, a poor soluble chloride, which puts it in the 1st group;

          • it also forms lead(II) sulfide $ce{PbS}$, insoluble in water and diluted acids, which also puts it in the 2nd group.


          One reason for putting lead in both groups is that the chloride is somewhat of a borderline case in terms of being insoluble enough to appear in Group I. Group II represents a more complicated analysis but is more sensitive for lead.






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
            $endgroup$
            – Oscar Lanzi
            58 mins ago






          • 1




            $begingroup$
            @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
            $endgroup$
            – andselisk
            56 mins ago
















          3












          $begingroup$

          Simply because lead(II) fits both analytical groups:




          • it forms lead(II) chloride $ce{PbCl2}$, a poor soluble chloride, which puts it in the 1st group;

          • it also forms lead(II) sulfide $ce{PbS}$, insoluble in water and diluted acids, which also puts it in the 2nd group.


          One reason for putting lead in both groups is that the chloride is somewhat of a borderline case in terms of being insoluble enough to appear in Group I. Group II represents a more complicated analysis but is more sensitive for lead.






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
            $endgroup$
            – Oscar Lanzi
            58 mins ago






          • 1




            $begingroup$
            @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
            $endgroup$
            – andselisk
            56 mins ago














          3












          3








          3





          $begingroup$

          Simply because lead(II) fits both analytical groups:




          • it forms lead(II) chloride $ce{PbCl2}$, a poor soluble chloride, which puts it in the 1st group;

          • it also forms lead(II) sulfide $ce{PbS}$, insoluble in water and diluted acids, which also puts it in the 2nd group.


          One reason for putting lead in both groups is that the chloride is somewhat of a borderline case in terms of being insoluble enough to appear in Group I. Group II represents a more complicated analysis but is more sensitive for lead.






          share|improve this answer











          $endgroup$



          Simply because lead(II) fits both analytical groups:




          • it forms lead(II) chloride $ce{PbCl2}$, a poor soluble chloride, which puts it in the 1st group;

          • it also forms lead(II) sulfide $ce{PbS}$, insoluble in water and diluted acids, which also puts it in the 2nd group.


          One reason for putting lead in both groups is that the chloride is somewhat of a borderline case in terms of being insoluble enough to appear in Group I. Group II represents a more complicated analysis but is more sensitive for lead.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 41 mins ago









          Oscar Lanzi

          15.2k12646




          15.2k12646










          answered 1 hour ago









          andseliskandselisk

          15.3k649109




          15.3k649109








          • 1




            $begingroup$
            Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
            $endgroup$
            – Oscar Lanzi
            58 mins ago






          • 1




            $begingroup$
            @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
            $endgroup$
            – andselisk
            56 mins ago














          • 1




            $begingroup$
            Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
            $endgroup$
            – Oscar Lanzi
            58 mins ago






          • 1




            $begingroup$
            @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
            $endgroup$
            – andselisk
            56 mins ago








          1




          1




          $begingroup$
          Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
          $endgroup$
          – Oscar Lanzi
          58 mins ago




          $begingroup$
          Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive.
          $endgroup$
          – Oscar Lanzi
          58 mins ago




          1




          1




          $begingroup$
          @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
          $endgroup$
          – andselisk
          56 mins ago




          $begingroup$
          @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily.
          $endgroup$
          – andselisk
          56 mins ago


















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